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FinnZ [79.3K]
2 years ago
6

The number of people who attended a concert on Friday was 3/4 the number of people who attended the same concert on Saturday. A

total of 840 people attended the concert on those two days. How many people attended the concert on Saturday?
Mathematics
1 answer:
LiRa [457]2 years ago
8 0

On Saturday, 4/4 of the amount of people attended.  On Friday, 3/4 of the amount on Saturday attended.  We have 7 parts (3 from Friday and 4 from Saturday).

840/7 = 120.

Thus, 360 people attend on Friday and 480 on Saturday.

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The list shows numbers in order from least to greatest. Negative 34, negative 2 and three-fourths, blank, negative 1.5, 0, 2.3,
blsea [12.9K]

Options

  • -2.5
  • -2
  • -1\dfrac{9}{10}
  • -1

Answer:

(B) -2

Step-by-step explanation:

Given the list

-34.-2\dfrac{3}{4} ,x, -1.5,0,2.3,10,25\dfrac15

This list has been arranged in order from the least to the greatest.

We are required to find an Integer that can be inserted on the blank line (I have used x) in the list.

An integer is defined as a positive or negative whole number.

Out of the given options, only -1 and -2 are integers. However:

  • -1 is greater than -1.5

Therefore, it cannot be our result.

The correct answer is -2.

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2 years ago
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The graphs below have the same shape. What is the equation for the red graph?
Serhud [2]
Your answer would be B because even though it's the same shape the red shape is 2 times bigger.......your exponent 4 stays 4
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2 years ago
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Mr Russo exchanged 200 euros for 270 dollars.how man dollars would he get for 300 euros
Nostrana [21]

200 euros       300 euros

--------------- = -----------------------------

270 dollars      x dollars

using cross products

200 * x = 270 * 300

divide each side by 200

x = 270 * 300/200

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2 years ago
A machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%). Prior to shipm
AURORKA [14]

Answer:

(a) 0.0686

(b) 0.9984

(c) 0.0016

Step-by-step explanation:

Given that a machine produces parts that are either defect free (90%), slightly defective (3%), or obviously defective (7%).

Let A, B, and C be the events of defect-free, slightly defective, and the defective parts produced by the machine.

So, from the given data:

P(A)=0.90, P(B)=0.03, and P(C)=0.07.

Let E be the event that the part is disregarded by the inspection machine.

As a part is incorrectly identified as defective and discarded 2% of the time that a defect free part is input.

So, P\left(\frac{E}{A}\right)=0.02

Now, from the conditional probability,

P\left(\frac{E}{A}\right)=\frac{P(E\cap A)}{P(A)}

\Rightarrow P(E\cap A)=P\left(\frac{E}{A}\right)\times P(A)

\Rightarrow P(E\cap A)=0.02\times 0.90=0.018\cdots(i)

This is the probability of disregarding the defect-free parts by inspection machine.

Similarly,

P\left(\frac{E}{A}\right)=0.40

and \Rightarrow P(E\cap B)=0.40\times 0.03=0.012\cdots(ii)

This is the probability of disregarding the partially defective parts by inspection machine.

P\left(\frac{E}{A}\right)=0.98

and \Rightarrow P(E\cap C)=0.98\times 0.07=0.0686\cdots(iii)

This is the probability of disregarding the defective parts by inspection machine.

(a) The total probability that a part is marked as defective and discarded by the automatic inspection machine

=P(E\cap C)

= 0.0686 [from equation (iii)]

(b) The total probability that the parts produced get disregarded by the inspection machine,

P(E)=P(E\cap A)+P(E\cap B)+P(E\cap C)

\Rightarrow P(E)=0.018+0.012+0.0686

\Rightarrow P(E)=0.0986

So, the total probability that the part produced get shipped

=1-P(E)=1-0.0986=0.9014

The probability that the part is good (either defect free or slightly defective)

=\left(P(A)-P(E\cap A)\right)+\left(P(B)-P(E\cap B)\right)

=(0.9-0.018)+(0.03-0.012)

=0.9

So, the probability that a part is 'good' (either defect free or slightly defective) given that it makes it through the inspection machine and gets shipped

=\frac{\text{Probabilily that shipped part is 'good'}}{\text{Probability of total shipped parts}}

=\frac{0.9}{0.9014}

=0.9984

(c) The probability that the 'bad' (defective} parts get shipped

=1- the probability that the 'good' parts get shipped

=1-0.9984

=0.0016

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Answer:

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