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2 years ago

14

Sams annual college tuition will be $230 more than ryan's annual college tuition after sams college tuition increase by 10% next

year. If ryan's current tuition is $22,200, what sams current tuition

1 answer:

Alik [6]2 years ago

3 0

Answer:

Sounds like Sam better pull it together

Step-by-step explanation:

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In a certain classroom ,12.5% of the students own at least one pet. If there are 32 students in the classroom,how many students

Y_Kistochka [10]

Answer:

28

Step-by-step explanation:

Given that 12.5% of students own at least 1 pet, then the percentage of students who do not own a pet is

100% - 12.5% = 87.5%

Calculate 87.5% of 32, that is

$\frac{87.5}{100}$ × 32

= 0.875 × 32 = 28 ← number of students who do not own a pet

8 0

2 years ago

Read 2 more answers

If a conditional statement is “If the sun shines, people will be in good moods”, what is the statement “If the sun does not shin

77julia77 [94]

Answer:

C. Inverse

Step-by-step explanation:

The second statement is the inverse, because in an inverse, the hypothesis and the conclusion are both negated. In this case, the sun doesnt shine and the people wont be in a good mood, as opposed to the sun will shine, and the people will be in a good mood.

7 0

1 year ago

A regional bus between Fort Collins and Denver mostly uses the high-occupancy vehicle (HOV) lane but it does have to cross two i

Liula [17]

Answer:

0.058 is the required probability.

Step-by-step explanation:

We are given the following PMF in the question:

x: 0 1 2

p(x): 0.24 0.15 0.61

$Z=X_1 + X_2$

Z can take values 0, 1, 2, 3, 4.

We have to compute the value of P(Z=0)

$(Z=X_1+X_2) \\P(Z=0)=P(X1=0)+P(X2=0) \\P(Z=0)=0.24\times 0.24\\P(Z=0) =0.0576\approx 0.058$

Thus,

$P(Z = 0) = 0.058$

7 0

2 years ago

Suppose we have a group of 10 light users and 10 heavy users. what is the probability that exactly 3 of the 20 users are hiv pos

dmitriy555 [2]

Answer: The answer is 30%.

Step-by-step explanation: Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.

We have the following four possible cases -

(i) All 3 are light users.

(ii) 1 is a light user and 2 are heavy users.

(iii) 2 are light users and 1 is a heavy user.

(iv) All 3 are heavy user.

Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

$p\\\\=\dfrac{3\times 0.45+1\times 0.45+2\times 0.55+2\times 0.45+1\times 0.55+3\times 0.55}{20}\\\\=\dfrac{6}{20}\\\\=0.3\\\\=30\%.$

Thus, the probability is 30.

4 0

1 year ago

A woman at a point A on the shore of a circular lake with radius r=4 wants to arrive at the point C diametrically opposite A on

levacccp [35]

Attached is a drawing to set up the problem, hopefully that helps.
The red lines are tracing the rowing and walking to get to other side.
dR = distance rowed
dw = distance walked
x = the angle in which to start rowing initially

dR can be found by using Law of cosines
$dR = \sqrt{4^2 +4^2 - 2(4)(4) cos(180-2x)} = 4\sqrt{2}\sqrt{1-cos(180-2x)}$
dw is arc length, which is just radius*arc
$dW = 4*2x = 8x$

next we need t set up a function for Time in terms of x.
This is so we can minimize the time it takes to get to other side.
Time = distance/rate

$T = \frac{dR}{5} + \frac{dW}{10} = \frac{4 \sqrt{2}}{5} \sqrt{1-cos(180-2x)}+\frac{4}{5} x$
Finally, take derivative and set equal to 0
Once you solve for x, plug it back into Time function to obtain final answer.

6 0

2 years ago