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baherus [9]
1 year ago
9

Zane is a dangerous fellow who likes to go rock climbing in active volcanoes. one time while inside a volcano, he heard some rum

bling, so he decided to climb up out of there as quickly as he could. he climbed up at a rate of 444 meters per second. after 333 seconds, he was 131313 meters below the edge of the volcano. how far was zane below the edge of the volcano when he started climbing?
Mathematics
1 answer:
defon1 year ago
5 0
From the given scenario is this particular item, the equation that can be derived for the distance traveled after x seconds is,
                            y = d₀ + (4)x
Substituting the known values x and y in order to solve for d₀ will give us an answer of,
                           13 = d₀ + 4(3)
                                    d₀ = 1 
Thus, the answer is 1 m. 
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The Bakhshali Manuscript shows that another method for calculating nonperfect squares was being used in India by 400 CE. Use thi
vovikov84 [41]
<span>The nearest perfect square that is less than 22 is 16, whose square root is 4. 

</span><span>Add the square root from step 1 to 3/4 to get 4.75.

</span>Calculate the quantity one-half times the square of  divided by the value found in step 2, or 4.75. (1/2  * (3/4)^2) <span>÷ 4.75 = 0.06.
</span>
Subtract the value found in step 3 from the value found in step 2, or 4.75.
The approximate value of <span>√22 is 4.69.</span>
7 0
2 years ago
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The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =
madreJ [45]
So we are given a system:
3x-2y+3z=0\\&#10;-3x - 5y - 5z= -21
Substitute x = 2 we get the system:
-2y+3z=-6\\&#10;- 5y - 5z= -15
Multiply the first equation by -5 and the second by 2 we get the system:
10y-15z=30\\&#10;- 10y - 10z= -30
Adding the two equations we get :
-25z=0\text{ then}z=0.
We find the value of y by using any of the other equations like this:
-2y=-6\\y=3.
Final solution:
z=0,y=3
8 0
1 year ago
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John took all his money from his savings account. He spent ​$110 on a radio and 4/11 of what was left on presents for his friend
svp [43]

Answer:

$1210

Step-by-step explanation:

Let x be total amount

First John spent $110 on a radio and 4/11 of what was left on presents for his friends so he was left with

\frac{7}{11}(x-110)=\frac{7}{11}x-70

Then he put 2/5 of his remaining money into a checking account

\frac{3}{5}\left(\frac{7}{11}x-70\right)

Rest he donated to charity

420=\frac{3}{5}\left(\frac{7}{11}x-70\right)\\\Rightarrow \left(\frac{7}{11}x-70\right)=\frac{2100}{3}\\\Rightarrow \frac{7}{11}x-70=700\\\Rightarrow \frac{7}{11}x=770\\\Rightarrow x=1210

Hence total amount of money John originally had was $1210

8 0
1 year ago
In the figure, angle ZYX is measured in degrees. The area of the shaded sector can be determined using the formula StartFraction
tensa zangetsu [6.8K]

<u>The given options are:</u>

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.

(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.

(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.

Answer:

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

Step-by-step explanation:

The area of the shaded sector can be determined using the formula:

\frac{m\angle ZYX}{360^\circ} \cdot \pi r^2

m\angle XYZ=$Central angle of XYZ\\\pi r^2$=Area of a Circle

360^\circ =$Total Angle

Therefore, the formula is:

\dfrac{m\angle ZYX}{360^\circ} \cdot \pi r^2\\\text{Area of XYZ}=\dfrac{\text{Cental Angle of XYZ}}{\text{Total Angle}} X \text{Area of the Circle}

Therefore, the formula is best explained by Option A.

7 0
2 years ago
Prove this (sinx-tanx)(cosx-cotx)=(sinx-1)(cosx-1)
Ilya [14]

<span><span>(<span>sinx</span>−<span>tanx</span>)</span><span>(<span>cosx</span>−<span>cotx</span>)</span></span>

<span>=<span>(<span>sinx</span>−<span><span>sinx</span><span>cosx</span></span>)</span><span>(<span>cosx</span>−<span><span>cosx</span><span>sinx</span></span>)</span></span>

<span>=<span>sinx</span><span>(1−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(1−<span>1<span>sinx</span></span>)</span></span>

<span>=<span>sinx</span><span>(<span><span>cosx</span><span>cosx</span></span>−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(<span><span>sinx</span><span>sinx</span></span>−<span>1<span>sinx</span></span>)</span></span>

<span>=<span><span>sinx</span><span>cosx</span></span><span>(<span>cosx</span>−1)</span><span><span>cosx</span><span>sinx</span></span><span>(<span>sinx</span>−1)</span></span>

<span>=<span>(<span>cosx</span>−1)</span><span>(<span>sinx</span>−1<span>)</span></span></span>

6 0
1 year ago
Read 2 more answers
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