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Likurg_2 [28]
2 years ago
7

The principal is collecting data to determine how many graduation tickets will be needed by students at the next graduation. She

randomly asks 3 students from Mr. Winking's Class which has 16 students in it. How many different groups of 3 does the principal have to pick from?
560

3360

4096

2.0923 X 10^13
Mathematics
2 answers:
nadya68 [22]2 years ago
8 0

<em>*</em><em>100% Correct answers</em>

Question 1

A movie theater was putting up their posters in the frames they had installed on the wall for upcoming attractions. They have 8 new movie posters and only 4 installed frames along the wall to hang them. So, they wont be able to use them all. In how many different ways can they arrange the new movie posters in the frames?

1680

Question 2

At a mall there are 5 jewelry stores. Allison is looking to purchase a necklace but only has time to visit 3 jewelry stores. In how many paths could she take to visit 3 of the 5 stores at the mall?

60

Question 3

The principal is collecting data to determine how many graduation tickets will be needed by students at the next graduation. She randomly asks 3 students from Mr. Winking's Class which has 16 students in it. How many different groups of 3 does the principal have to pick from?

560

Question 4

How many 2 topping pizzas are possible at Padre Juan's Pizza if there are 12 toppings to choose from and the order in which you put the toppings on the pizza does not matter?

66

Question 5

The Miss Teen Georgia pageant is taking place and there are 25 contestants. How many different ways could the pageant have a winner, runner up, and a 2nd place winner.  

13800

LUCKY_DIMON [66]2 years ago
8 0

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

Number of students = 16

Number of students in a group = 3

We need to find the number of different groups of 3 that the principal have to pick from.

We need to select 3 from 16 so, we will use "Combination":

So, the number of different groups would be

^{16}C_3\\\\=560

Hence, first option is correct.

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A scientist running an experiment starts with 100 bacteria cells. These bacteria double their population every 15 hours. Find ho
IRISSAK [1]
<h2>Hello!</h2>

The answer is: 23.77 hours

<h2>Why?</h2>

Total(t)=Start*2^\frac{t}{15}

Where:

Total(t) is equal to the amount for a determined time (in hours)

<em>Start</em> is the original amount

<em>t </em>is the time in hours.

For example, it's known from the statement that the bacteria double their population every 15 hours, so it can be written like this:

Total(15)=100*2^\frac{15}{15}=100*2^{1}=100*2=200

To calculate how long it takes for the bacteria cells to increase to 300, we should do the following calculation:

300=100*2^{\frac{t}{15} } } \\\frac{300}{100}=2^{\frac{t}{15} } }\\log(3)=log(2^{\frac{t}{15} })\\\\\\log(3)=\frac{t}{15}*log2\\t=\frac{log(3)}{log(2)} *15=23.77

So, to know if we are right, let's replace 23.77 h in the equation:

Total(t)=100*2^\frac{23.77}{15}=299.94

and 299.94≅300

Have a nice day!

8 0
2 years ago
Read 2 more answers
Find the standard deviation of the following data. Answers are rounded to the nearest tenth. 5, 5, 6, 12, 13, 26, 37, 49, 51, 56
kogti [31]

Answer:

24.2(to the nearest tenth)

Step-by-step explanation:

The question is ungrouped data type

standard deviation =√ [∑ (x-μ)² / n]

mean (μ)=∑x/n

           = \frac{5+5+6+12+13+26+37+49+51+56+56+84}{12}

          =33.3

x-μ   for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49

∑ (x-μ)² will be = 7028.59

standard deviation = √(7028.59 / 12)

                      =24.2

     

6 0
2 years ago
A dentist wants to find out how often her patients floss their teeth. Which samples are biased? Check all that apply. all her pa
ArbitrLikvidat [17]

Answer:

all her patients patients with no cavities

patients younger than 18

every patient with braces

Step-by-step explanation:

when a sample is selected in a manner that some elements, in this case patients, of population have higher or lower probability of sampling then that sample is biased.

From given case, all the following are biased samples

all her patients patients with no cavities

patients younger than 18

every patient with braces

because they are non-random sample of a population in which all other elements were not equally likely to be chosen!

7 0
2 years ago
Read 2 more answers
Market-share-analysis company Net Applications monitors and reports on Internet browser usage. According to Net Applications, in
ASHA 777 [7]

Answer:

a) There is a 2.43% probability that exactly 8 of the 20 Internet browser users use Chrome as their Internet browser.

b) There is an 80.50% probability that at least 3 of the 20 Internet browsers users use Chrome as their Internet browser.

c) The expected number of Chrome users is 4.074.

d) The variance for the number of Chrome users is 3.2441.

The standard deviation for the number of Chrome users is 1.8011.

Step-by-step explanation:

For each Internet browser user, there are only two possible outcomes. Either they use Chrome, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Google Chrome has a 20.37% share of the browser market. This means that p = 0.2037

20 Internet users are sampled, so n = 20.

a.Compute the probability that exactly 8 of the 20 Internet browser users use Chrome as their Internet browser.

This is P(X = 8).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{20,8}.(0.2037)^{8}.(0.7963)^{12} = 0.0243

There is a 2.43% probability that exactly 8 of the 20 Internet browser users use Chrome as their Internet browser.

b.Compute the probability that at least 3 of the 20 Internet browsers users use Chrome as their Internet browser.

Either there are less than 3 Chrome users, or there are three or more. The sum of the probabilities of these events is decimal 1. So:

P(X < 3) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.2037)^{0}.(0.7963)^{20} = 0.0105

P(X = 1) = C_{20,1}.(0.2037)^{1}.(0.7963)^{19} = 0.0538

P(X = 2) = C_{20,2}.(0.2037)^{2}.(0.7963)^{18} = 0.1307

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0105 + 0.0538 + 0.1307 = 0.1950

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1950 = 0.8050

There is an 80.50% probability that at least 3 of the 20 Internet browsers users use Chrome as their Internet browser.

c.For the sample of 20 Internet browser users, compute the expected number of Chrome users

We have that, for a binomial experiment:

E(X) = np

So

E(X) = 20*0.2037 = 4.074

The expected number of Chrome users is 4.074.

d.For the sample of 20 Internet browser users, compute the variance and standard deviation for the number of Chrome users.

We have that, for a binomial experiment, the variance is

Var(X) = np(1-p)

So

Var(X) = 20*0.2037*(0.7963) = 3.2441

The variance for the number of Chrome users is 3.2441.

The standard deviation is the square root of the variance. So

\sqrt{Var(X)} = \sqrt{3.2441} = 1.8011

The standard deviation for the number of Chrome users is 1.8011.

6 0
2 years ago
If a and b are two integers then closure property states then​
Margarita [4]

Your question has been heard loud and clear.

If a and b are two integers , then closure property states that the product of the two integers a and b , which is ab , is also an integer.

Thank you

4 0
2 years ago
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