Answer:
Step-by-step explanation:
So there is a 3% probability that an athlete is using EPO .
The probability of showing positive on a test when you've used it is 0.99.
3% x 0.99= 2.97%
The probability of a positive result without EPO is 0.1
97% x 0,1 = 9,7 %
My guess is that 2.97% + 9,7% = 12.67% or 0.1267.
I don't know i may be wrong because you've put as an answer 0.0297 but if you like you may take only the first part of the answer.
The answer would be B) 5.90x > 236
This is because Jay needs at least 236 therefore the money he earns from working at the ice cream parlor would need to be higher than 236.

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive
So as x approaches infinity then y approaches infinity
as x approaches -infinity then y approaches infinity
The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.
Now we check the x intercepts of the first graph
x intercepts of first graph is -4 and 2
Plug in -4 for x in f(x) and check whether we get 0


Now plug in 2 for x and check

So -4 and 2 are the x intercepts that satisfies f(x)
Hence first option is the graph of 
Answer: 2.1 Pull out like factors :
6s - 2r = -2 • (r - 3s)
Equation at the end of step
((0-(9•(6s-4r)))+3s)--14•(r-3s)
Pulling out like terms
4.1 Pull out like factors : 6s - 4r = -2 • (2r - 3s)
Equation at the end of step
((0--18•(2r-3s))+3s)--14•(r-3s)
Final result :
<u>50r - 93s</u>
Answer:
a. 
Step-by-step Explanation:
Given:
Distance Ottawa to Québec = 425 km
Initial flight rate = v + 60
Return flight rate = v - 40

Required:
Flight times difference of the initial and return flights
Solution:
=>Flight time of the initial flight:


=>Flight time of the return flight:

=>Difference in flight times:





