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TEA [102]
2 years ago
6

An Adult ticket at an amusement park costs $24.95 and a child's ticket costs $15.95. A group of 10 people paid $186.50 to enter

the park. How many were adults
Mathematics
1 answer:
leva [86]2 years ago
6 0

Answer:

There were 3 adults

Step-by-step explanation:

Step 1: Derive the first expression

a+c=10...equation 1

where;

a=number of adults

c=number of children

And total number of people=10

Step 2: Derive the second expression;

Total cost of tickets=(price per child ticket×number of children)+(price per adult ticket×number of adults)

where;

Total cost of tickets=$186.50

price per child ticket=$15.95

price per adult ticket=$24.95

number of children=c

number of adults=a

replacing;

(15.95×c)+(24.95×a)=186.5

24.95 a+15.95 c=186.5....equation 2

Step 3: Combine equation 1 and 2 and solve simultaneously

24.95 a+15.95 c=186.5

-

24.95(a+c=10)

(24.95 a-24.95 a)+(15.95 c-24.95 c)=186.5-(24.95×10)

-9 c=-63

c=-63/-9

c=7

replace the value for c in equation 1

a+c=10

a+7=10

a=10-7

a=3

There were 3 adults

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The Tennessee Tourism Institute (TTI) plans to sample information center visitors entering the state to learn the fraction of vi
baherus [9]

Answer: 2185

Step-by-step explanation:

Let p be the proportion of visitors are campers.

Given : The Tennessee Tourism Institute (TTI) plans to sample information center visitors entering the state to learn the fraction of visitors who plan to camp in the state.

The prior proportion of visitors are campers : p=0.35

Allowable error : E= 2%= 0.02

We know that the z-value for 95% confidence = z_c=1.96

Then by Central Limit Theorem , the required sample size would be :

n=p(1-p)(\dfrac{z_{c}}{E})^2

\Rightarrow\ n=0.35(1-0.35)(\dfrac{1.96}{0.02})^2\\\\ n= 0.35(0.65)(9604)

Simply , we get

n=2184.91\approx2185  [Rounded to the next whole number.]

Hence, the smallest sample size to estimate the population proportion of campers =2185

7 0
2 years ago
Kirti knows the following information from a study on cold medicine that included 60 participants: 30 participants in total rece
GalinKa [24]
The frequency table is attached.

Since there were 30 people out of the 60 that received cold medicine, that means that 60-30=30 people did not.

Since 26 people had a cold longer than 7 days, this means 60-26=34 had a cold that was less than or equal to 7 days.

14 people had a cold longer than 7 days and received medicine; this means that 26-14=12 people had a cold longer than 7 days and did not receive medicine.

30-14=16 people received medicine and had a cold less than or equal to 7 days.

30-12=18 people did not receive medicine and had a cold less than or equal to 7 days.

4 0
2 years ago
In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t
victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is   p =\frac{1}{5}

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5  

b

The mean is  \mu = 20

The standard deviation is \sigma=4

c

The probability, P =0.0002

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability Pe = 0.0003

The probabilities P \approx Pe

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

                  p =\frac{1}{5}

                    =0.2

The mean of this distribution is mathematical represented as

           \mu = np

substituting the value

         \mu = 100 * 0.2

             \mu = 20

The standard deviation is mathematically represented as

         \sigma = \sqrt{np (1-p)}

substituting the value

           = \sqrt{100 * 0,2 (1-0.2)}

           \sigma=4

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

               P=P(X \ge 34 )

By standardizing the normal approximation we have that

              P(X \ge 34) \approx P(Z \ge z)

Now z is mathematically evaluated as

               z = \frac{x-\mu}{\sigma }

Substituting values

             z = \frac{34-20}{4}

               =3.5

So  using the z table the P(Z \ge 3.5) is  0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small  So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

 

6 0
2 years ago
Tomer owns a daycare center called kidz kare. One afternoon he collected the age of each person in kidz kare. The following hist
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Answer:

3/10

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Part B: Find an irrational number that is between 9.5 and 9.7. Explain why it is irrational. Include the decimal approximation o
fgiga [73]
Irrational number between 9.5 and 9.7...

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the decimal approximation to the nearest hundredth is : 9.68

4 0
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