Find the number of ordered quadruples (a, b, c,

A building has eight levels above ground and one level below ground. The height of each level from floor to ceiling is 14 1/2 fe

vovangra [49]

The net change in elevation is 72.5 feet

6 0

2 years ago

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What is the sum of all positive integers smaller than $1000$ that can be written in the form $100\cdot 2^n$, where $n$ is an int

netineya [11]

Answer:

The sum is 1575.

Step-by-step explanation:

Consider the provided information.

It is given that positive integers smaller than 1000 and that can be written in the form $100\cdot 2^n$

Where n is integer that means the value of n can be a positive number or a negative number.

For n = 0

$100\cdot 2^{0}=100$

For n=-1

$100\cdot 2^{-1}=50$

For n=-2

$100\cdot 2^{-2}=25$

For n = -3 the obtained number is not an integer.

Now consider the positive value of n.

For n=1

$100\cdot2^1 = 200$

For n=2

$100\cdot2^2 = 400$

For n=3

$100\cdot2^3 = 800$

For n=4 the obtained number is greater than 1000.

Now add all the numbers.

$100+50+25+200+400+800=1575$

Hence, the sum is 1575.

6 0

2 years ago

In this activity, you'll calculate a probability and use it to predict the result of repeating a simple chance-based trial many

kompoz [17]

1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5

3 0

2 years ago

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A pet store has 15 birds and 75 fish.

Ludmilka [50]

Answer:

1/5

Step-by-step explanation:

6 0

1 year ago

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If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2

erica [24]

Hello,

y=5+3*cos (2(x-π/3))

The function is periodic with periode=2π.

-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8

8 0

2 years ago