Salt flows in at a rate of (5 g/L)*(3 L/min) = 15 g/min.
Salt flows out at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.
So the net flow rate of salt, given by 
in grams, is governed by the differential equation,
which is linear. Move the 
term to the right side, then multiply both sides by 
:
Integrate both sides, then solve for :
Since the tank starts with 5 g of salt at time 
, we have
The time it takes for the tank to hold 20 g of salt is 
such that
Answer:Factor the polynomial
3(a−4b)2
Answer:
<h2>-1/2</h2>
Step-by-step explanation:
Given the function 
, the average rate of change of g(x) over the interval [-2,4], is expressed as shown below;
Rate of change of the function is expressed as g(b)-g(a)/b-a
where a - -2 and b = 4
average rate of change of g(x) over the interval [-2,4] will be;
To solve 16x18, you may split it up into a smaller increment you understand. Like 16x2, which equals 32. (18/2 is 9) multiply 32 by 9. you get your answer 288.
Answer:
The correct answer would be option C.
Step-by-step explanation:
Since he gives the dog 3 liters of water and 500 grams of food a day we know that on the fifth day the dog will have gotten 15 liters of water and 2,500 grams of food.
