I thibk its 5 tell if im right
Answer:
answer C
Step-by-step explanation:
you need to add all the components
and as 1400+100=1500 it gives the formula at the answer C
hope this helps
Answer:
<2.1130913087, 4.53153893518>; <−3.03108891325, −1.75>; <−0.91799760455, 2.78153893518>
Step-by-step explanation:
Bruce's vector is <5cos(90-25), 5sin(90-25)> = <5cos(65), 5sin(65)> ≈ <2.1130913087, 4.53153893518>
The wind's vector is <3.5cos(270-60), 3.5sin(270-60)> = <3.5cos(210), 3.5sin(210)> ≈ <−3.03108891325, −1.75>
You add them together to find his actual motion:
<−0.91799760455, 2.78153893518>
Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Total Volume would be 6 + 4 = 10 pints
Let's calculate the volume of alcohol in final solution:
20% * 6 = 1.2 pints
10% * 4 = .4 pints
Total = 1.6 pints of alcohol in 10
Percentage = (1.6/10) * 100 = 16 per cent.
answer is A
