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lana [24]
2 years ago
11

Which equations are equivalent to Three-fourths + m = negative StartFraction 7 over 4 EndFraction? Select three options. m = Sta

rtFraction 10 over 4 EndFraction m = negative StartFraction 10 over 4 EndFraction m = negative five-halves StartFraction 11 over 4 EndFraction + m = negative one-fourth Negative five-fourths + m = negative StartFraction 15 over 4 EndFraction
Mathematics
2 answers:
marishachu [46]2 years ago
5 0

Answer:

1)  m = negative StartFraction 10 over 4 EndFraction

2) m = negative five-halves

3) m = -\frac{7}{4} - \frac{3}{4}

Step-by-step explanation:

<u>The given equation is:</u>

=> \frac{3}{4} +m = -\frac{7}{4}

Subtracting 3/4 to both sides

=> m = -\frac{7}{4} - \frac{3}{4}

=> m = \frac{-10}{4}

=> m = -\frac{5}{2}

Alex777 [14]2 years ago
3 0

Answer:

-5/2 ye

cause ya do the math

Step-by-step explanation:

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The best correct answer is option E. If two or more polygons are congruent, then rigid transformations can be used to map one polygon onto the other. <span>Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object.</span>
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Which of the following is the best definition of the domain
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Answer:

Step-by-step explanation:

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The factory quality control department discovers that the conditional probability of making a manufacturing mistake in its preci
Anni [7]

Answer:

The probability that a defective ball bearing was manufactured on a Friday = 0.375

Step-by-step explanation:

Let the event of making a mistake = M

The event of making a precision ball bearing production on Monday = Mo

The event of making a precision ball bearing production on Tuesday = T

The event of making a precision ball bearing production on Wednesday = W

The event of making a precision ball bearing production on Thursday = Th

The event of making a precision ball bearing production on Friday = F

the conditional probability of making a manufacturing mistake in its precision ball bearing production is 4% on Tuesday, P(M|T) = 4% = 0.04

4% on Wednesday, P(M|W) = 0.04

4% on Thursday, P(M|Th) = 0.04

8% on Monday, P(M|Mo) = 0.08

and 12% on Friday = P(M|F) = 0.12

The Company manufactures an equal amount of ball bearings (20 %) on each weekday, Hence, the probability that a random precision ball bearing was made on a particular day of the week, is mostly the same for all the five working days.

P(Mo) = 0.20

P(T) = 0.20

P(W) = 0.20

P(Th) = 0.20

P(F) 0.20

The probability that a defective ball bearing was manufactured on a Friday = P(F|M)

P(F|M) = P(F n M) ÷ P(M)

P(F n M) = P(M n F)

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

We can obtain each of these probabilities by using the expression for conditional probability.

P(Mo n M) = P(M|Mo) × P(Mo) = 0.08 × 0.20 = 0.016

P(T n M) = P(M|T) × P(T) = 0.04 × 0.20 = 0.008

P(W n M) = P(M|W) × P(W) = 0.04 × 0.20 = 0.008

P(Th n M) = P(M|Th) × P(Th) = 0.04 × 0.20 = 0.008

P(F n M) = P(M|F) × P(F) = 0.12 × 0.20 = 0.024

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

P(M) = 0.016 + 0.008 + 0.008 + 0 008 + 0.024 = 0.064

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P(F n M) = P(M n F) = 0.024

P(M) = 0.064

P(F|M) = P(F n M) ÷ P(M) = (0.024/0.064) = 0.375

Hope this Helps!

4 0
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Question 1(Multiple Choice Worth 2 points)
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These are 3 questions and 3 answers.

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That is the line that has the open circle around y = 4, and that is the limit searched.

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To determine each limit you use the function from the side the value of x is being approached.

Note, that since the two limits are different it is said that the limit of the function as it approaches 2 does not exist.

3) 
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\lim_{x \to \ 3^-} f(x) = -1

To find the limit when the function is approached to 3 from the left you follow the line that ends with the open circle at (3, -1).

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