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sladkih [1.3K]
2 years ago
14

Shelly states that the triangles below are similar. Which proportion supports her statement? Triangle S T R. Side S T is 6, T R

is 4, R S is 8. Triangle N M O. Side O N is 15, N M is 20, M O is 10. StartFraction 8 Over 4 EndFraction = StartFraction 15 Over 10 EndFraction StartFraction 8 Over 10 EndFraction = StartFraction 4 Over 20 EndFraction StartFraction 6 Over 4 EndFraction = StartFraction 20 Over 10 EndFraction StartFraction 8 Over 6 EndFraction = StartFraction 20 Over 15 EndFraction
Mathematics
2 answers:
kirza4 [7]2 years ago
7 0

Answer:

the dude above me is right - the answer is D on ed.genuity

Step-by-step explanation:

20/15 and 8/6 both simplify to 1.333333333

Strike441 [17]2 years ago
5 0

Answer:

D: 8/6=20/15

Step-by-step explanation:

it's correct

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ACD is a triangle and B is a point on AC. AB = 8cm and BC is 6cm. Angle BCD = 48° and angle BDC = 50°. (a) Find the length of BD
FromTheMoon [43]

Answer:

  • 5.8206 cm
  • 10.528 cm
  • 23.056 cm^2

Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

  BD/sin(48°) = BD/sin(50°)

  BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

__

(b) We can use the Law of Cosines to find AD.

  AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

  AD^2 ≈ 110.841

  AD ≈ √110.841 ≈ 10.5281 . . . cm

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(c) The area of ∆ABD can be found using the formula ...

  A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

  A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

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Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

5 0
2 years ago
44 students completed some homework and the histogram shows information about the times taken. Work out an estimate of the inter
Vilka [71]

Answer:

q1=11

q3= 33

Step-by-step explanation:

The data set has 44 number of students. The first quartile is 25 %  of the numbers in the data set . So

25 % of 44 = 25/100 * 44= 0.25 *44 = 11

So the first quartile lies at 11.

Similarly the third quartile lies at the 75 % of the numbers of the data set . So

75 % of 44 = 75/100 * 44= 0.75 *44 = 33

So the third quartile lies at 33.

5 0
2 years ago
A water tank leaks 5 gallons of water each day. What integer represents the change in the number of gallons of water in the tank
andrey2020 [161]

Answer:

35 is the integer that represents the change in number of gallons of water in the tank after 7 days

Step-by-step explanation:

The water tank leaks 5 gallons in one day.

So if there is leakage of 5 gallons a day, then after 7 days the total leakage will be:

Total Leakage = Leakage per day * Total number of days

= 5 Gal/day * 7 day

= 35 Gallons

So, 35 is the integer that represents the change in number of gallons of water in the tank after 7 days ..

5 0
2 years ago
A certain firm has plants a, b, and c producing respectively 35\%, 15\%, and 50\% of the total output. The probabilities of a no
TEA [102]

The proportion of production that is defective and from plant A is

... 0.35·0.25 = 0.0875

The proportion of production that is defective and from plant B is

... 0.15·0.05 = 0.0075

The proportion of production that is defective and from plant C is

... 0.50·0.15 = 0.075

Thus, the proportion of defective product that is from plant C is

... 0.075/(0.0875 +0.0075 +0.075) = 75/170 = 15/34 ≈ 44.12%

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P(C | defective) = P(C&defective)/P(defective)

8 0
2 years ago
Un globo busca aterrizar en medio de dos ciudades A y B, cuya distancia entre si es de 200 km. Si se mide el ángulo de elevación
scoundrel [369]

Answer:

h \approx 59.898\,km

Step-by-step explanation:

El diagrama trigonométrico que representa el enunciado es incluido abajo como adjunto. Las siguientes relaciones trigonométricas describen la localización del globo. (The trigonometric diagram representing the statement is included below as attachment. The following trigonometric relations describes the location of the balloon):

\tan 27^{\circ} = \frac{h}{x}

\tan 36^{\circ} = \frac{h}{200-x}

A continuación, se obtiene la distancia horizontal: (The horizontal distance is obtained hereafter):

x \cdot \tan 27^{\circ} = (200-x)\cdot \tan 36^{\circ}

x \cdot (\tan 27^{\circ} + \tan 36^{\circ})= 200\cdot \tan 36^{\circ}

x = \frac{200\cdot \tan 36^{\circ}}{\tan 27^{\circ}+ \tan 36^{\circ}}

x \approx 117.557\,km

La altura aproximada del globo es (The approximated height of the globe is):

h = x\cdot \tan 27^{\circ}

h \approx 59.898\,km

7 0
2 years ago
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