Answer:
46.125 or 46 1/8
Step-by-step explanation:
2(3×8-15÷16)
=2(24-15÷16)
= 48 - 30/16
= (768 - 30)/16
= 738/16
= 46.125 or 46 1/8
Answer:
4585.8 feet
Step-by-step explanation:
If we draw the triangle, the opposite side to 3° angle would be "10" less than total height of 250 because Nick is 10 feet above water level, so that side will be:
250 - 10 = 240
The hypotenuse of the triangle is the length of line of sight. We can call this "x".
So, using trigonometric ratio of sine (opposite/hypotenuse), we can write:
Now, we cross multiply and solve for x, line of sight length:
Answer:
29119.66666...+14561.3333...=43681, 209ft^2, not square feet.
Step-by-step explanation:
<em>"One side of a rectangle is 3 feet shorter than twice the other side find the sides if the area is 209 feet squared"</em>
Ok, so this is a tricky one- <em> 209 feet squared, </em>not 209 square feet, therefore the area is 209^2, or 43,681.
Next, let's define our variables-
<em>x= the "other side"</em>
<em>z= 3 feet shorter than twice side</em>
We can now make these (useful) equations
z=2x-3
43681= (2x-3)+x
We will focus on the latter for now-
Simplify
43681= (2x-3)+x
43681= 2x-3+x
43681= 3x-3
+3
43684=3x
/3
14561.3333...=x
z=2x-3
z=2*(14561.3333)-3
z=29119.66666....
29119.66666...+14561.3333...=43681
The right answer is:
<em>area B = area C</em>
We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.
