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1 year ago

Nam owns a used car lot. He checked the odometers of the cars and recorded how far they had driven. He

Mathematics

2 answers:

statuscvo [17]1 year ago

7 0

Answer:

a histogram

Step-by-step explanation:

You can count easily from hiistogram how many vehicles had driven more than 200,000 km (kilometers) and that's not the case with the box plot

adell [148]1 year ago

7 0

Answer:

is b then a

Step-by-step explanation:

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The volume of clay used to build a cylindrical pillar with a height of 9 centimeters is 324π cubic centimeters. The area of the

stealth61 [152]

Area=height times base (for some prisms including cylinders)
vcylinder=hpir²
h=height
therefor pir²=base area
vcylinder=height times aeraofbase

given
h=9
v=324pi
324pi=9(basearea)
divide both sides by 9
36pi=areabase

the area of te base is 36pi square cm (put 36 in the blank since th pi is alredy there)

3 0

2 years ago

Read 2 more answers

Mrs. Anderson surveyed her class and asked each student, "How many hours do you spend

jonny [76]

Answer:

Step-by-step explanation:

8 0

2 years ago

The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc

gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

$\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}$

Write W in terms of U and V.

$\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}$

Define U and V using geometric series formula.

$\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}$

Use sum of geometric series formula.

$2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})$

Simplify.

$-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})$

Therefore, r = 9 and m = 112.

8 0

1 year ago

Which shapes have the same volume as the given rectangular prism?<br><br>base area = 50 cm^2

icang [17]

Answer:The first one

Step-by-step explanation:

V rectangular prism = Area of the base *5

5 0

2 years ago

If jl= 10x-2 JK = 5x-8 and KL = 7x-12 find KL

natta225 [31]

JK+KL=JL
(5x-8)+7x-12=10x-2
(add common terms together)
12x-20=10x-2
(get the term with x alone on one side of the equation)
2x=18
(divide by 2 to get x alone)
x=9

Find KL:
KL=7(9)-12
KL=51

8 0

2 years ago