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castortr0y [4]
2 years ago
15

The midsegment of triangle ABC is LM. What is the length of AC if LM is 15 inches long?

Mathematics
2 answers:
Arte-miy333 [17]2 years ago
6 0
The answer is 30 inches.
tresset_1 [31]2 years ago
4 0

Answer:

30 inches

Step-by-step explanation:

It is given that The mid segment of triangle ABC is LM. We know that A midsegment is the line segment connecting the midpoints of two sides of a triangle. A triangle midsegment is parallel to the third side of the triangle and is half of the length of the third side.

Consider triangle ABC and LM is the midsegment of this triangle. Then, according to the definition of mid segment, we have:

LM=\frac{AC}{2}

⇒15=\frac{AC}{2}

⇒AC=15{\times}2

⇒AC=30inches

Thus, the length of AC is 30 inches.

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Step-by-step explanation:


A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.


This polynomial has roots -4, -1, and 5. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.


In this polynomial:


Root -4 has even multiplicity of 4 so it only touches and does not cross through.


Root -1 has odd multiplicity of 3 so crosses through.


Root 5 has even multiplicity of 6 so it only touches and does not cross through.


Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.


To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.

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We are asked to solve for the lateral surface area of the cylinder such that the formula that we can used is Lateral Surface Area = 2pi*r*h where "r" represents the radius of the cylinder and "h" represents the height of the cylinder. In this problem, we are given with the following values:
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Answer:

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Step-by-step explanation:

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C

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