The midsegment of triangle ABC is LM. What is the length of AC if LM is 15 inches long?

Mathematics

2 answers:

Arte-miy333 [17]2 years ago

6 0

The answer is 30 inches.

tresset_1 [31]2 years ago

4 0

Answer:

30 inches

Step-by-step explanation:

It is given that The mid segment of triangle ABC is LM. We know that A midsegment is the line segment connecting the midpoints of two sides of a triangle. A triangle midsegment is parallel to the third side of the triangle and is half of the length of the third side.

Consider triangle ABC and LM is the midsegment of this triangle. Then, according to the definition of mid segment, we have:

$LM=\frac{AC}{2}$

⇒ $15=\frac{AC}{2}$

⇒ $AC=15{\times}2$

⇒ $AC=30inches$

Thus, the length of AC is 30 inches.

You might be interested in

nia has number cards for 2,3,8,9, and 5. what are all the different ways nia can arrange the cards to show only even numbers whi

VladimirAG [237]

There are 6 different ways:

23,598
23,958
25,398
25,938
29,538
29,358

3 0

2 years ago

the members of the gardening group plan to build a walkway through the garden as formed by the IHOP potenuse of each of the four

aliya0001 [1]

Answer:

50.24 yards

Step-by-step explanation:

We will use the pythagorean theorem to find hypotenuse of each of the 4 triangles.

Pythagorean Theorem is $Hypotenuse^2=OneLeg^2+AnotherLeg^2$

For Spinach area, two of the legs are 8 and 6. Solving for hypotenuse:

$hyp^2=6^2+8^2\\hyp^2=100\\hyp=10$

For watermelon area, two of the legs are 12 and 8. Solving for hypotenuse:

$hyp^2=12^2+8^2\\hyp^2=208\\hyp=\sqrt{208}$

in red peppers area, the hypotenuse is already given as 15. But we need to find one leg since that will be the leg of the triangle in tomatoes area. Hypotenuse is 15 and one leg is 12, so the other leg is:

$15^2=12^2+eg^2\\15^2-12^2=leg^2\\leg=9$