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Paul [167]
2 years ago
12

Shawna and her best friend Keisha go shopping. The function p(x) = 3x4 + 2x3 − 4x2 + 21 represents how much money each girl spen

t based on the number of hours they were shopping. If Shawna and Keisha each go shopping for 2 hours, how much money did they spend together? $37 $69 $101 $138 Question 9(M
Mathematics
1 answer:
tino4ka555 [31]2 years ago
5 0

Answer:

$69

Step-by-step explanation:

Given the amount of money each girl spent based on the number of hours they were shopping modeled by the function p(x) = 3x4 + 2x3 − 4x2 + 21

To get how much they spend together if each go shopping for 2hours, we will substitute x = 2 into the given function as shown:

p(2) = 3(2)⁴ + 2(2)³ − 4(2)² + 21

p(2) = 3(16) + 2(8) − 4(4) + 21

p(2) = 48 + 16 − 16 + 21

p(2) = 48+21

p(2) = 69

Therefore they spend $69 together

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Step-by-step explanation:

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In a café, drinks are priced according to what size they are.
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Dmitri wants to cover the top and sides of the box shown with glass tiles that are 3 5 mm square How many tiles does he need 20
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Lets split the box in pieces and then add:
top = 20*15 = 300
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sidesB = 2*9*15 = 270, is multiplied  by 2 cause there are 2 sides like this
so in total we have:
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if we express this quantity in mm^2 we have:
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Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade
Tom [10]

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6 0
2 years ago
Cones A and B both have volume cubic 48π units, but have different dimensions. Cone A has radius 6 units and height 4 units. Fin
kogti [31]

Answer:

r = 2 units

h= 36 units

Step-by-step explanation:

Given That:

Cones A and B both have volume cubic 48π units

The volume of a cone = \frac{1}{3} \pi r^2h

So for cone A

V_A = \frac{1}{3} \pi r_A^2 h_A

Volume for cone B

V_B = \frac{1}{3} \pi r_B^2 h_B

Due to different dimensions;

Cone A has

radius = 6 units

height = 4 units

To determine the one possible radius and height for cone B;

we have

\frac{1}{3} \pi r_A^2 h_A =\frac{1}{3} \pi r_B^2 h_B

\frac{1}{3} \pi (6)^2 (4) =\frac{1}{3} \pi r_B^2 h_B

150.9=\frac{1}{3} \pi r_B^2 h_B

150.9=1.047r_B^2 h_B

r_B^2 h_B=144.12

r_B^2 h_B=144

Therefore; the only possible way for this equation is :

r_B = (2)\\h_B = 36

If we are to check: we will realize that;

r_B^2h_B = (2)^2*36 =144

Therefore, the possible radius for the cone B = 2 units and height = 36 units. Hence from the question, we are told they both have the same volume of 48 π units.

7 0
2 years ago
Read 2 more answers
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