Answer:
60.42%
Step-by-step explanation:
Number of home runs hit by Adrian Beltre in 2004 = 48
Number of home runs hit by Adrian Beltre in 2005 = 19
To find:
Percentage decrease in home run production from 2004 to 2005.
Solution:
To find the percentage decrease, first of all we need to find the decrease in the number of home runs and then we will divide with the number of home runs in 2004 and then finally will multiply the result with 100 to get the percentage decrease.
Decrease in the number of home runs = Number of home runs in 2004 - Number of home runs in 2005 = 48 - 19 = 29
Therefore, by 60.42% Beltre's home run production has decreased from 2004 to 2005.
78 cents because 12 gallons equals 48 quarts. 37.20/48=.776
1m = 100cm
1cm → 0.5m
1cm → 0.5 · 100cm = 50cm
The scale: 
length = 26.8cm · 50 = 1,340cm = 13.40m
width = 12.2cm · 50 = 610cm = 6.10m
The area of the court:
A = 13.40 · 6.10 = 81.74 m²
<h3>Simplifying </h3>
9x + -31 = 43
<h3>Reorder the terms:</h3>
-31 + 9x =43
<h3>Solving</h3>
-31 + 9x =43
<h3>Solving for variable 'x' .</h3><h3>Move all terms containing x to the left, </h3>
Add '31' to each side of the equation .
0 + 31 +9x = 43 + 31
<h3>Combine like terms: </h3>
-31 + 31 =0
0 + 9x = 43 +31
9x = 43 + 31
<h3>Combine like terms:</h3>
43 + 31 =74
9x = 74
<h3>Divide each side by '9'</h3>
x = 8. 222222222
<h3>Simpifying</h3>
x = 8.222222222
