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Ad libitum [116K]
2 years ago
5

Eli had $10 but he lost some of it. He mom doubled the money he had left. Eli wrote the expression 2(10-k) how much money he has

now, where k is the amount of money he lost. Aisha wrote another correct expression , 20-2k, to also how much money Eli has now
Mathematics
1 answer:
bezimeni [28]2 years ago
7 0

Answer:

Step-by-step explanation:

According to the first expression:

2(10-k): where,

2:shows the double amount of money which ELI has

10:shows the amount of money which ELI had at the starting.

k:shows the amount of money which is lost.

10-k:shows the amount of money which ELI has after losing some amount.

According to the second expression:

20-2k where,

20:shows the twice of initial amount.

k: is the amount of money which is lost

2k:s hows the twice of amount which is lost

20-2k: shows the amount of money which is left with ELI after his mom gave him some money....

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The gas mileage for a certain vehicle can be approximated by m=−0.05x2+3.5x−49, where x is the speed of the vehicle in mph. Dete
Whitepunk [10]

Answer:

<h2>14mph</h2>

Step-by-step explanation:

Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;

m = −0.05x²+3.5x−49

when m= 9

9 = −0.05x²+3.5x−49

−0.05x²+3.5x−49 = 9

0.05x²-3.5x+49 = -9

Multiplying through by 100

5x²+350x−4900 = 900

Dividing through by 5;

x²+70x−980 = 180

x²+70x−980 - 180 = 0

x²+70x−1160 = 0

Using the general formula to get x;

a = 1, b = 70, c = -1160

x = -70±√70²-4(1)(-1160)/2

x = -70±√4900+4640)/2

x = -70±(√4900+4640)/2

x = -70±√9540/2

x =  -70±97.7/2

x = -70+97.7/2

x = 27.7/2

x = 13.85mph

x ≈ 14 mph

Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph

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Melanie is very concerned with avoiding late fees. The table shows her choices for paying her bills. Method Bill Payment Methods
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Answer:

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Step-by-step explanation:

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What transformations are used in transforming the parent graph y = x, to obtain the graph of c (x) = StartFraction 5 Over 9 EndF
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Given that:

Parent equation : y=x

Transformed function : c(x)=\dfrac{5}{9}(x-32)

Solution:

Let Parent equation be f(x)=x. Then,

c(x)=\dfrac{5}{9}f(x-32)      ...(1)

The translation is defined as

c(x)=kf(x+a)+b                .... (2)

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If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (1) and (2), we get

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b=0, so there is no vertical shift.

Therefore, the graph of parent function compressed vertically by factor \dfrac{5}{9} and shifts 32 units right to get the graph of c(x).

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