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dmitriy555 [2]
2 years ago
10

The energy expended by a bird per day, E, depends on the time spent foraging for food per day, F hours. Foraging for a shorter t

ime requires better territory, which then requires more energy for its defense.1 Find the foraging time that minimizes energy expenditure if E=0.25F+1.7/f^2
Mathematics
1 answer:
Veronika [31]2 years ago
7 0

Answer:

Therefore F=2.387 hours gives a minimum value of energy expenditure E.

Step-by-step explanation:

Given that,

The energy expended by a bird per day

E=0.25 F+\frac{1.7}{F^2}

Differentiating with respect to F

E'=0.25 -\frac{3.4}{F^3}

Again differentiating with respect to F

E''=\frac{10.2}{F^4}

Now set E'=0

0.25 -\frac{3.4}{F^3}=0

\Rightarrow \frac{3.4}{F^3}=0.25

\Rightarrow F^3=\frac{3.4}{0.25}

\Rightarrow F=2.387

Now E''|_{F=2.387}=\frac{10.2}{2.387^4}>0

Since, E''>0 at F=2.387, So at F=2.387 , E has minimum value.

Therefore F=2.387 hours that minimizes energy expenditure.

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A gardener has 640 feet of fencing to fence in a rectangular garden. One side of the garden is bordered by a river and so it doe
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Answer:

  • 160 ft (out from the river)
  • 320 ft (parallel to the river)

Step-by-step explanation:

Let x represent the length of fence parallel to the river. Then the dimension of perpendicular to the river will be half the remaining fence: (640-x)/2. The total area will be ...

  A = x(640-x)/2

This is the equation of a parabola that opens downward. It has zeros at x=0 and x=640, so its axis of symmetry is x = (0+640)/2 = 320. That is, the peak of the area curve is found when x=320.

The dimensions of the garden with the largest area are 160 ft wide by 320 ft long, where the long side is the river side.

6 0
2 years ago
The cost of producing x bags of dog food is given by C(x) = 800 + 400 + 10x - x where 0 SX 55000. Find the marginal-cost functio
nikdorinn [45]

Answer:

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

Completed question;

The cost of producing x bags of dog food is given by C(x) = 800 + √(400 + 10x² - x) where 0≤x≤55000. Find the marginal-cost function.

The marginal-cost function is c'(x)=

(Use integers or fractions for any numbers in the expression.)

Step-by-step explanation:

The marginal-cost function is c'(x)= = dC(x)/dx

Where;

C(x) = 800 + √(400 + 10x² - x)

c'(x) = d(800 + √(400 + 10x² - x) )/dx

Using function of function rule of differentiation or chain rule;

c'(x) = (20x-1)×(1/2√(400 + 10x² - x))

c'(x) = (20x-1)/(2√(400 + 10x² - x))

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

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Coach Jump is standing on a platform watching the football team practice. If the platform is 12 feet high and the quarterback is
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Answer:

Why don't you know this its so easy

Step-by-step explanation:

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Two classes have a total of 50 students. One class has 6 more students than the other. How may students are in the larger class
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Subtract 6 from 50:
50-6 = 44
Divide 44 by 2:
44/2 = 22

add 6:

22+6 = 28

There is 22 in the smaller class and 28 in the larger class.
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Juanita makes $42 an hour at work. She has to take time off work to purchase her dress, so each hour away from work costs her $4
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If this is a go math question you can look it up
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