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dmitriy555 [2]
2 years ago
10

The energy expended by a bird per day, E, depends on the time spent foraging for food per day, F hours. Foraging for a shorter t

ime requires better territory, which then requires more energy for its defense.1 Find the foraging time that minimizes energy expenditure if E=0.25F+1.7/f^2
Mathematics
1 answer:
Veronika [31]2 years ago
7 0

Answer:

Therefore F=2.387 hours gives a minimum value of energy expenditure E.

Step-by-step explanation:

Given that,

The energy expended by a bird per day

E=0.25 F+\frac{1.7}{F^2}

Differentiating with respect to F

E'=0.25 -\frac{3.4}{F^3}

Again differentiating with respect to F

E''=\frac{10.2}{F^4}

Now set E'=0

0.25 -\frac{3.4}{F^3}=0

\Rightarrow \frac{3.4}{F^3}=0.25

\Rightarrow F^3=\frac{3.4}{0.25}

\Rightarrow F=2.387

Now E''|_{F=2.387}=\frac{10.2}{2.387^4}>0

Since, E''>0 at F=2.387, So at F=2.387 , E has minimum value.

Therefore F=2.387 hours that minimizes energy expenditure.

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What is the value angle marked x?
Anton [14]

Answer: x =104

Step-by-step explanation:

If we draw the black line shown in the figure, two isosceles triangles are formed, and the base angles of the isosceles triangles are the same. The red angles are the same and the green ones too. The 104 degree angle is the sum of the red angle and the green angle, and x is also the sum of the red angle and the green angle, therefore x = 104.

7 0
2 years ago
A solar panel dealer acquires is used panel for $9,000, with terms FOB shipping point. Compute total inventory cost assigned to
malfutka [58]

Answer:

Total inventory cost is $9,965.

Step-by-step explanation:

The terms free on board FOB shipping point implies that the delivery of a good is taken by the buyer after it left the supplier's shipping dock. Therefore, any other relevant cost incurred afterwards will be paid by the buyer.

From the all the cost listed in the question, the $1,500 for sales staff salaries, $110 for online advertising, and $300 for lawn care are NOT related to the inventory cost because they are administrative and sales expenses.

Therefore, the total inventory cost can be calculated using the following relevant cost:

Acquisition cost = $9,000

Transportation-in by train = $280

Shipping insurance = $135

Used panel restoration = $550

Therefore, we have:

Total inventory cost = Acquisition cost + Transportation-in by train + Shipping insurance + Used panel restoration = $9,000 + $280 + $135 + $550 = $9,965.

3 0
2 years ago
How do i do this some one please explain
Talja [164]

Well since we already have our unit per mile.

We know that 1 mile = $3.50

And that the tow company towed the car 12 miles.

So we would have to multiply 12 by $3.50

soo..

12 x $3.50 = $42.00

So your answer is D. $42.00

4 0
1 year ago
Use the X method to find the solutions of<br><br> 6x2 + 2x – 20 = 0
SVEN [57.7K]
The X method?
2x=8
X=4
5 0
2 years ago
Read 2 more answers
A quality control manager at an auto plant measures the paint thickness on newly painted cars. A certain part that they paint ha
Scorpion4ik [409]

Answer:

78.88% probability that the mean thickness in the sample of 100 points is within 0.1 mm of the target value

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 2, \sigma = 0.8, n = 100, s = \frac{0.8}{\sqrt{100}} = 0.08

What is the probability that the mean thickness in the sample of 100 points is within 0.1 mm of the target value?

This is the pvalue of Z when X = 2 + 0.1 = 2.1 subtracted by the pvalue of Z when X = 2 - 0.1 = 1.9. So

X = 2.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2.1 - 2}{0.08}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 1.9

Z = \frac{X - \mu}{s}

Z = \frac{1.9 - 2}{0.08}

Z = -1.25

Z = -1.25 has a pvalue of 0.1056

0.8944 - 0.1056 = 0.7888

78.88% probability that the mean thickness in the sample of 100 points is within 0.1 mm of the target value

8 0
2 years ago
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