Answer:
S(2001) = 19.23
S(2002) = 37.22
Step-by-step explanation:
Given that;
S(t) = 0.73t^2 + 15.8t +2.7
t = 0 corresponding 2000
t = 1 then, its mean year 2001
so
S(2001) = 0.73(1)^2 + 15.8(1) +2.7
= 0.73 + 15.8 + 2.7
S(2001) = 19.23
also
t = 2 then, it means 2002
so
S(2002) = 0.73(2)^2 + 15.8(2) +2.7
= 2.92 + 31.6 + 2.7
S(2002) = 37.22
Answer:
c=1
Step-by-step explanation:
subtract 1 with 10, outcome is 1. subtract both sides by 9 to deduct the 9. and you get 1
Answer:<em><u>
π
. </u></em>
Given:

Using Gauss's Law = ∫∫s E ·dS
= ∫∫∫ div E dV,
⇒ Divergence (Gauss') Theorem
= ∫∫∫ (1+1+6) dV
= 8×(volume of the hemisphere, radius "a")
= 8× (
)(4/3)π
<em><u>=
π
. </u></em>
Gonna be somewhere about 5 inches if I’m correct I hope this helps:)
Answer:
a) 0.9
b) Mean = 1.58
Standard Deviation = 0.89
Step-by-step explanation:
We are given the following in the question:
A marketing firm is considering making up to three new hires.
Let X be the variable describing the number of hiring in the company.
Thus, x can take values 0,1 ,2 and 3.

a) P(firm will make at least one hire)

Also,


b) expected value and the standard deviation of the number of hires.
![E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89](https://tex.z-dn.net/?f=E%28x%5E2%29%20%3D%20%5Cdisplaystyle%5Csum%20x_i%5E2P%28x_i%29%5C%5C%3D0%280.1%29%20%2B%201%280.4%29%20%2B%204%280.32%29%20%2B9%280.18%29%20%3D%203.3%5C%5CV%28x%29%20%3D%20E%28x%5E2%29-%5BE%28x%29%5D%5E2%20%3D%203.3-%281.58%29%5E2%20%3D%200.80%5C%5C%5Ctext%7BStandard%20Deviation%7D%20%3D%20%5Csqrt%7BV%28x%29%7D%20%3D%20%5Csqrt%7B0.8036%7D%20%3D%200.89)