84.12 * 19.3.....notice how, when added, u have 3 spaces to the right of the decimal....so there is 3 decimal places..
84.12 * 19.3 = 1623.516...3 decimal places
so ur answer is : 19.3
Y=4 Because you divide 18 by 4.50 and then just put a point on positive four on your graph.
Answer:
(a) X follows a Binomial distribution
(b) (i) P(X ≥ 2) = 0.28348
P(X = 1) = 0.39601
P(X ≤ 3) = 0.98800
Step-by-step explanation:
(a) In this situation, the variable X equal to the number of ducks that are infected follows a <em>Binomial distribution</em> because we have:
- n identical and independent events: The 7 ducks that are selected at random
- 2 possible results for every event: success and fail. We can call success if the duck is infected and fail if the duck is not infected.
- A probability p of success and 1-p of fail: There is a probability p equal to 15% that the ducks have the infection and a probability of (100%-15%) that they don't.
(b) So, the probability that X ducks are infected is calculated as:


Then, Probability P(X = 1) is equal to:

At the same way, probability P(X ≥ 2) is equal to:
P(X ≥ 2) = P(2) + P(3) + P(4) + P(5) + P(6) + P(7)
P(X ≥ 2) = 0.2097 + 0.0617 + 0.0109 + 0.0011 + 0.00006 + 0.00002
P(X ≥ 2) = 0.28348
And probability P(X ≤ 3) is equal to:
P(X ≤ 3) = P(0) + P(1) + P(2) + P(3)
P(X ≤ 3) = 0.3206 + 0.3960 + 0.2097 + 0.0617
P(X ≤ 3) = 0.988
Answer:
The simplified form of the expression is
.
Step-by-step explanation:
The expression is:

The division rule of exponents is:

The negative exponent rule is:

Simplify the expression as follows:
![\frac{x^{-3}\cdot y^{2}}{x^{4}\cdot y^{6}}=[x^{-3-4}]\times [y^{2-6}]](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B-3%7D%5Ccdot%20y%5E%7B2%7D%7D%7Bx%5E%7B4%7D%5Ccdot%20y%5E%7B6%7D%7D%3D%5Bx%5E%7B-3-4%7D%5D%5Ctimes%20%5By%5E%7B2-6%7D%5D)

Thus, the simplified form of the expression is
.
To solve this you need to know Pythagorean theorem.
First, EG is 24, so the halfway points are 12. Knowing Pythagorean triples, you can use 5,12,13 and 12,16,20.
DF = 5+16
DF = 21
If you don't know Pythagorean triples, I have worked it out on the image attached.