All categories

2 years ago

Chuck has a gross pay of $815.70. By how much will Chuck’s gross pay be reduced if he has the following items withheld?

Mathematics

2 answers:

ipn [44]2 years ago

8 0

Answer:

Chuck will get $686.67.

Step-by-step explanation:

Chuck has a gross pay of $815.70.

Federal tax of $56

Social Security tax that is 6.2% of his gross pay; $0.062\times815.70=50.57$ dollars

Medicare tax that is 1.45% of his gross pay; $0.0145\times815.70=11.82$ dollars

State tax that is 19% of his federal tax; $0.19\times56=10.64$ dollars

Total deductions are = $56+50.57+11.82+10.64=129.03$ dollars

Hence, Chuck's gross pay will be reduced by $129.03 and he will get $815.70-129.03$ = $686.67

lapo4ka [179]2 years ago

7 0

It will be minus $129.04

You might be interested in

The product of 84.12 and which number will have three decimal places? 4.22 10.51 14.163 19.3

dedylja [7]

84.12 * 19.3.....notice how, when added, u have 3 spaces to the right of the decimal....so there is 3 decimal places..

84.12 * 19.3 = 1623.516...3 decimal places

so ur answer is : 19.3

3 0

2 years ago

Read 2 more answers

PLEASE HELP WILL MARK BRAINLIEST (if possible).......................Braden bought 18 pencils for $4.50. Let x represent the num

Bingel [31]

Y=4 Because you divide 18 by 4.50 and then just put a point on positive four on your graph.

8 0

2 years ago

Read 2 more answers

It is claimed that 15% of the ducks in a particular region have patent schistosome infection. Suppose that seven ducks are selec

Marizza181 [45]

Answer:

(a) X follows a Binomial distribution

(b) (i) P(X ≥ 2) = 0.28348

P(X = 1) = 0.39601

P(X ≤ 3) = 0.98800

Step-by-step explanation:

(a) In this situation, the variable X equal to the number of ducks that are infected follows a Binomial distribution because we have:

n identical and independent events: The 7 ducks that are selected at random
2 possible results for every event: success and fail. We can call success if the duck is infected and fail if the duck is not infected.
A probability p of success and 1-p of fail: There is a probability p equal to 15% that the ducks have the infection and a probability of (100%-15%) that they don't.

(b) So, the probability that X ducks are infected is calculated as:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

$P(x)=\frac{7!}{x!(7-x)!}*0.15^{x}*(1-0.15)^{7-x}$

Then, Probability P(X = 1) is equal to:

$P(1)=\frac{7!}{1!(7-1)!}*0.15^{1}*(1-0.15)^{7-1}=0.3960$

At the same way, probability P(X ≥ 2) is equal to:

P(X ≥ 2) = P(2) + P(3) + P(4) + P(5) + P(6) + P(7)

P(X ≥ 2) = 0.2097 + 0.0617 + 0.0109 + 0.0011 + 0.00006 + 0.00002

P(X ≥ 2) = 0.28348

And probability P(X ≤ 3) is equal to:

P(X ≤ 3) = P(0) + P(1) + P(2) + P(3)

P(X ≤ 3) = 0.3206 + 0.3960 + 0.2097 + 0.0617

P(X ≤ 3) = 0.988

6 0

2 years ago

Read 2 more answers

Which is the simplified form of the expression (StartFraction (x Superscript negative 3 Baseline) (y squared) Over (x Superscrip

Vlad [161]

Answer:

The simplified form of the expression is $\frac{1}{x^{7} y^{4}}$ .

Step-by-step explanation:

The expression is:

$\frac{x^{-3}\cdot y^{2}}{x^{4}\cdot y^{6}}$

The division rule of exponents is:

$a^{m}\div a^{n}=a^{m-n}$

The negative exponent rule is:

$a^{-m}=\frac{1}{a^{m}}$

Simplify the expression as follows:

$\frac{x^{-3}\cdot y^{2}}{x^{4}\cdot y^{6}}=[x^{-3-4}]\times [y^{2-6}]$

$=x^{-7}\times y^{-4}\\\\=\frac{1}{x^{7} y^{4}}$

Thus, the simplified form of the expression is $\frac{1}{x^{7} y^{4}}$ .

8 0

2 years ago

Read 2 more answers

What is the length of the other diagonal DF? 5 cm 16 cm 21 cm 32 cm

frez [133]

To solve this you need to know Pythagorean theorem.

First, EG is 24, so the halfway points are 12. Knowing Pythagorean triples, you can use 5,12,13 and 12,16,20.

DF = 5+16
DF = 21

If you don't know Pythagorean triples, I have worked it out on the image attached.

3 0

2 years ago

Read 2 more answers