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2 answers:
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Answer:
In case (a) car makes 105° turn.
In case (b) car makes 75° turn.
In case (c) car makes 105° turn.
Step-by-step explanation:
Figure is redrawn To explain properly (in attachment)
Given : streets are parallel means ║
,
AB - 4th street , CD - 3rd street and XY - King Ave.
∠XLA = 75°
To find : (a) ∠XLB
(b) ∠LMD (left onto 3rd streat means left of car)
(c) ∠YMD (right means right side of car)
∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are
supplementary)
∠XLB + 75° = 180°
∠XLB = 180 - 75
∠XLB = 105°
∴ In case (a) car makes 105° turn.
∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)
∠LMD = 75°
∴ In case (b) car makes 75° turn.
∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are
supplementary)
∠YMD + 75° = 180°
∠YMD = 180 - 75
∠YMD = 105°
∴In case (c) car makes 105° turn.
Answer:
At most 800 magazines the company can print daily with the remaining number of ink cartridges.
Step-by-step explanation:
We are given the following in the question:
The above inequality gives the relation for daily supply of ink cartridges where N is the number of newspaper and M is the number of magazines.
Number of newspaper to be printed daily,N = 8000
We have to find the number of magazines at most can the company print daily with the remaining number of ink cartridges.
Puting the value in the given inequality,
Thus, at most 800 magazines the company can print daily with the remaining number of ink cartridges.