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brilliants [131]
2 years ago
6

The scatter chart below displays the residuals verses the dependent variable, x. Which of the following conclusions can be drawn

based upon this scatter chart? a. The residuals are normally distributed. b. The model over predicts the value of the dependent variable for small values and large values of the independent variable. c. The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship. d. The residuals have a constant variance.
Mathematics
1 answer:
lawyer [7]2 years ago
6 0

Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot

answer :  The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )

Step-by-step explanation:

The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship

<em>A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship </em>

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After clarification we see the respective diameters are

A = 2.3 \times 10^{-a}

B = 2.3 \times 10^{-b}

We're asked about the ratio

A:B =  2.3 \times 10^{-a} :  2.3 \times 10^{-b} = 10^{-a} : 10^{-b} = 10^b : 10^a = 10^{b-a} : 1

Now we can go through the choices.

A. If a = 4 and b = 6, then cell a is 100 times greater than cell b.

A:B=10^{6-4}:1 = 100:1

It would be more proper to say the diameter of cell A is 100 times the diameter of cell B, but yes, this is TRUE.

B. If a = 4 and b = 6, then cell b is 100 times greater than cell a.

FALSE. 10 to the minus 4 is 100 times bigger than 10 to the minus 6, so a is bigger.

C. If a = 4 and b = 6, then cell a is 2 times greater than cell b.

FALSE. We already calculated its 100 times bigger.

D. If a = 4 and b = 6, then cell b is 2 times greater than cell a.

FALSE.


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2 years ago
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A city manager made the graph below to represent the number of passengers that city buses can carry, where the number of passeng
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Data from 14 cities were combined for a​ 20-year period, and the total 280 ​city-years included a total of 107 homicides. After
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Answer:

P(0) =  0.6825

P(1) = 0.2607

Step-by-step explanation:

From the given information, the number of homicide is 107 and the total number of homicides per city –year is 280.

Let us denote the number of homicides per city-year as X.

The mean value, X is calculated as:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}  

Mean=   107/280 = 0.382  

The mean number of homicides per city- year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. The probability that zero homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=0) =  e  −0.382  (0.382)⁰​/1  

= (0.6825)(1) /1  

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Thus, the probability that zero homicides P(0) is 0.6825.

b. The probability that one homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=1) =  e  −0.382  (0.382)¹​/1  

= (0.6825)(0.382)/1  

P(X=1) = 0.2607

Thus, the probability that zero homicides P(0) is 0.2607.

​

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Answer: $680.00

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