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andrew11 [14]
2 years ago
10

How is the graph of y = negative RootIndex 3 StartRoot x minus 4 EndRoot transformed to produce the graph of y = negative RootIn

dex 3 StartRoot 2 x minus 4 EndRoot?

Mathematics
2 answers:
marishachu [46]2 years ago
6 0

Answer:

c on ed

Step-by-step explanation:

i j did it

SVEN [57.7K]2 years ago
3 0

Answer:

Multiply by ∛2 and translate the graph to left by 4 units.

Step-by-step explanation:

The initial function given is:

y = -∛(x - 4)

The transformed function is:

y = -∛(2x - 4)

Consider the initial function.

y = -∛(x - 4)

(Represented by Black line in the graph)

Multiply the function by ∛2. The function becomes:

y = -∛(x - 4) × ∛2

y = -∛(2)(x-4)

y = -∛(2x-8)

(Represented by Red line in the graph represents this function)

Translate the graph 4 units to the left by adding 4 to the x component:

y = -∛(2x-8+4)

y= -∛(2x - 4)

(Represented by Blue line in the graph)

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High school students from track teams in the state participated in a training program to improve running times. Before the train
Nataly [62]

Answer:

b. The values X and Y are independent therefore, the mean is 34 seconds and the standard deviation is 50 seconds

Step-by-step explanation:

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Before the training, the mean running time for the students to run a mile was 402 seconds with standard deviation 40 seconds.

This means that \mu_X = 402, \sigma_X = 40

After completing the program, the mean running time for the students to run a mile was 368 seconds with standard deviation 30 seconds.

This means that \mu_Y = 368, \sigma_Y = 30

Which of the following is true about the distribution of X-Y?

They are independent, so:

\mu = \mu_X - \mu_Y = 402 - 368 = 34

\sigma = \sqrt{\sigma_X^2+\sigma_Y^2} = \sqrt{40^2+30^2} = 50

This means that the correct answer is given by option b.

3 0
1 year ago
Find the percent of change from 688 qt to 172 qt.
Alekssandra [29.7K]

There is 75% decrease.

Step-by-step explanation:

Given,

Old value = 688 qt

New value = 172 qt

Change = New value - Old value

Change = 172 - 688

Change = -516 qt

The negative sign indicates decrease.

Decrease percent = \frac{Change}{Old\ value}*100

Decrease percent = \frac{516}{688}*100

Decrease percent = \frac{51600}{688}

Decrease percent = 75%

There is 75% decrease.

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/10196212
  • brainly.com/question/1021953

#LearnwithBrainly

3 0
2 years ago
Read 2 more answers
 PLEASE HELP: For the next RSM Award ceremony, it was decided to decrease the length of the main poster by 12% and to increase i
MrRissso [65]
Let me set an example to help solve this, say the poster is 100 inches by 90 inches. the length of the poster is reduced by 12% so subtract 12 from 100 to get you new length of 78 inches. the width is increased by 15% so multiply 90 by 15% to get 13.5 inches and add the to the 90 inches you have to get your new width of 103.5 inches. multiply them together to get your new area then divide the new area by the old area, subtract that number by 1 and multiply it by -1.
3 0
2 years ago
Julia examines the two triangles below and determines that .
baherus [9]

IN Δ MLN:


∠M = 18.3 , ∠L = 98.6 AND ∠N = 180 - (∠M + ∠L) = 180 - (18.3 + 98.6 ) = 63.1



IN Δ FGH:


∠F = 98.6 , ∠G = 61.1 AND ∠H = 180 - (∠F + ∠G ) = 180 - (98.6 + 61.1 ) = 20.3



∴ ONLY ∠N = ∠F = 98.6


There is no other <span>congruent </span>angles


So, The correct statement is :

Inaccurate. The triangles are not similar because angle M is not congruent to angle H, and angle N is not congruent to angle G.



8 0
2 years ago
Read 2 more answers
Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen
Irina-Kira [14]
Hi there!

PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)

Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1

PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.

Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers

ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
8 0
2 years ago
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