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2 years ago

50 points. Please quick.

Mathematics

1 answer:

Allisa [31]2 years ago

3 0

Answer:

Condition A.

A rectangle with four right angles

There can be many quadrilaterals satisfying this condition.

Condition B.

A square with one side measuring 5 inches

There can be only one quadrilateral satisfying this condition.

Condition C.

A rhombus with one angle measuring 43°

There can be many quadrilaterals satisfying this condition.

Condition D.

A parallelogram with one angle measuring 32°

There can be many quadrilaterals satisfying this condition.

Condition E.

A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.

There can be only one quadrilateral satisfying this condition.

Condition F.

A rectangle with adjacent sides measuring 4 inches and 3 inches.

There can be only one quadrilateral satisfying this condition

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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1 year ago

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2 years ago

There are two approaches to solving the equation -3x + 10 = 4x - 20 Subtract 4x from both sides. OR Add 3x to both sides. –7x +

Scrat [10]

Answer:

There are two approaches to solving the equation -3x + 10 = 4x - 20. The value of x after solving in both methods is 4.2857.

Solution:

Given, equation is -3x + 10 = 4x – 20.

We have to solve the given equation in two methods, now let us see the first method.

1st method ⇒ by subtracting 4x from both sides.

Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 – 4x = 4x – 20 – 4x ⇒ -3x – 4x = -20 – 10 ⇒ -7x = -30 ⇒ 7x = 30

Then, x = $\frac{30}{7}$

Now, let us use the 2nd method.

2nd method ⇒ by adding 3x on both sides.

Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 + 3x = 4x – 20 + 3x

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⇒ x = $\frac{30}{7}$

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