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alexandr1967 [171]
2 years ago
6

The lunch lady pushes a 100 kg zombie with 300 N of force. How much is the zombie accelerated?

Mathematics
2 answers:
rusak2 [61]2 years ago
4 0

Answer:

-2/2  -0.1  1/9

Step-by-step explanation:

Doss [256]2 years ago
3 0

Answer:

Answer:

-2/12, -0.1, 1/9

Step-by-step explanation:

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In 2009, a city with a population of 796,000 had 2,388 births. What is the number of births per 10,000 in the city?
Tom [10]
796,000/2388=10,000/x
796,000x= (2388*10,000)
796,000x/796,000=23,880,000/796,000
x=30 births
7 0
2 years ago
On a december day, the probability of snow is .30. the probability of a "cold" day is .50. the probability of snow and "cold" we
Svetradugi [14.3K]
Events A and B are independent if the following holds true:

P(A ∩ B) = P(A) * P(B)

where P(A ∩ B) is the probability of A and B, P(A) is the probability of A, and P(B) is the probability of B.

Setting A = "snow" and B = "cold weather", and plugging in the above numbers will give you the answer.
7 0
2 years ago
Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp. (a)How many
BigorU [14]

Answer:

a) 20 ways

b) 10 ways

Step-by-step explanation:

When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.

Part a)

We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2

General formula of permutations of n objects taken r at time is:

nPr=\frac{n!}{(n-r)!}

Using the value of n=5 and r=2, we get:

5P2=\frac{5!}{(5-2)!} =20

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.

Part b)

Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.

The general formula of combinations of n objects taken r at a time is:

nCr=\frac{n!}{r!(n-r)!}

Using the value of n=5 and r=2, we get:

5C2=\frac{5!}{2!(5-2)!} =10

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice does not matters.

3 0
2 years ago
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Which table shows a constant rate of change of –3? A 2-column table with 4 rows. Column 1 is labeled x with entries 3, 4, 5, 6.
Andrew [12]

Answer:

c

Step-by-step explanation:

6 0
2 years ago
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Shelia is dividing x4 – 4x3 + 4x2 – 6x + 5 by x – 1 using a division table. Quotient Divisor x3 – 3x2 + x – 5 x x4 –3x3 x2 A – 1
Hatshy [7]
Is there by answer choice? Or by a table?
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2 years ago
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