Answer:
- Time = approximately mid 2012
- Oil import rate = 3600 barrels
Step-by-step explanation:
<h3><em>Unclear part of the question</em></h3>
- I(t) = −35t² + 800t − 1,000 thousand barrels per day (9 ≤ t ≤ 13)
- According to the model, approximately when were oil imports to the country greatest? t = ?
<h3>Solution</h3>
Given the quadratic function
- <em>The vertex of a quadratic function is found by a formula: x = -b/2a</em>
<u>As per given function:</u>
<u>Then</u>
- t = - 800/2*(-35) = 11.43 which is within given range of 9 ≤ t ≤ 13
This time is approximately mid 2012.
<u>Considering this in the function, to get oil import rate for the same time:</u>
- l(11.43) = -35*(11.43)² + 800*11.43 - 1000 = 3571.4285
<u>Rounded to two significant figures, the greatest oil import rate was</u>:
374 = 33
272 = x
374/33 = 272/x
x=(33*272)/374=24 minutes
Answer:
C I think
Step-by-step explanation:
Answer:
It would be A, or the first graph
Step-by-step explanation:
So we’ve now created an equation
2x + 3y ≤ 6
From here, we can convert this into something easier to read
y ≤ -2/3x + 2
Now, we know that the y-intercept is 2 so either A or B
We also know the shaded area should be below the line (because the smallest part of the “≤” is facing the y).
Therefore, the answer is A
8,000,000 pennies equals $80,000. 1/.05=20
20 x $80,000=$1,600,000 more that the bank was able to lend
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