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2 years ago

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A local coffee store is curious about the size beverages their customers are ordering. The beverages come in three sizes: small,

medium, and large. An employee runs a simulation of 15 random outcomes using the values 1, 2, and 3 to represent small, medium, and large, respectively. What is the simulated probability that a customer will order the small beverage? 2 2 3 1 1 2 2 3 1 1 3 2 1 1 3

2 answers:

Digiron [165]2 years ago

6 0

Answer:

2 out of 5 or 6 out of 15

Step-by-step explanation:

In this pattern, there is two people ordering it every five times. You can write it out as 6/15 or simplify it as 2/5 (six-fifteenths and two-fifths)

lara31 [8.8K]2 years ago

4 0

<h2>Answer:</h2>

The simulated probability that a customer will order the small beverage is:

$\dfrac{2}{5}=0.4$

<h2>Step-by-step explanation:</h2>

The 1, 2, and 3 to represent small, medium, and large, respectively.

The simulation is as follows:

2 2 3 1 1 2 2 3 1 1 3 2 1 1 3

There are a total outcomes= 15

Also, the number of outcomes that the customer will order small beverage is: 6

( Since, 6 times such that 1 has occurred.

As 1 represent the simulation that the beverage comes in small size )

Hence, the simulated probability is:

$\dfrac{6}{15}=\dfrac{2}{5}=0.4$

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The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

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Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

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Answer: Gus skydived 32 times

Step-by-step explanation:

G = number of times that Gus skydives

N = number of times that Nico skydives

E= number of times that Emma skydives

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This means G = 4N

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This means E= 2N

If Emma has skydived 16 times,

That means E = 16

Put E = 16 in E= 2N,

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Put N= 8 in G = 4N

G =4×8 = 32

Gus skydived 32 times

Check

Nick skydived 8 times

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Answer:

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Step-by-step explanation:

Given:

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Let the length of the shortest timber be 'x' feet.

Now, in a right angled triangle, the longest length is called the hypotenuse.

As 15 feet is the largest length, it is the hypotenuse of the triangle. Now, applying Pythagoras theorem, we get:

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