Answer:
a) The data distribution consists of ( 7 )1's (denoting a foreign student) and ( 43 )0's (denoting a student from the U.S.).
b) The population distribution consists of the x-values of the population of 12,152 full-time undergraduate students at theuniversity, ( 6 )% of which are 1's (denoting a foreign student) and ( 94 )% of which are 0's (denoting a student from the U.S.).
c) The mean is ( 0.06 )
The standard deviation is ( 0.0336 )
The sampling distribution represents the probability distribution of the ( sample ) proportion of foreign students in a random sample of ( 50 ) students. In this case, the sampling distribution is approximately normal with a mean of ( 0.06 ) and a standard deviation of ( 0.0336 )
Step-by-step explanation:
Answer:
They each have 64
Step-by-step explanation:
let C = number of fish that Cecilia has --- then, O = 2C, where O = number of fish that Oscar has --- and T = O + 8 = 2C + 8, where T = number of fish that Tasha has --- then, C + O + T = C + 2C + (2C + 8) = 148 --- or, 5C + 8 = 148 --- or, 5C = 140 --- or, C = 140/5 = 28 --- and, O = 2C = 2(28) = 56 --- and, T = O + 8 = 56 + 8 = 64
Answer:
Step-by-step explanation:
- 13t - 3t = (13 - 3)t = 10t
- 3t - 13t = (3 - 13)t = -10t
- 10t ≠ -10t
They are not equivalent
<u>When t = 2</u>
- 13t - 3t = 13*2 - 3*2 = 26 - 6 = 20
- 3t - 13t = 3*2 - 13*2 = 6 - 26 = -20
Answer:
a) Null hypothesis:
Alternative hypothesis:
b) 
(1)
Replacing we got:
The p value for this case would be given by:
c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%
Step-by-step explanation:
Information given
n=400 represent the random sample taken
X=52 represent the workers belonged to unions
estimated proportion of workers belonged to unions
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic
represent the p value
Part a
We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:
Null hypothesis:
Alternative hypothesis:
Part b
The statistic is given by:
(1)
Replacing we got:
The p value for this case would be given by:
Part c
For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%
