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Lelu [443]
2 years ago
5

Freshmen and Sophomores Solve by setting up a system of linear equations with 2 variables and 2 unknowns. A total of 1,595 first

and second year college students gathered at a pep rally. The number of freshman exceeded the number of sophomores by 15. How many freshmen were at the pep rally? A) There were 790 freshmen at the pep rally. B) There were 795 freshmen at the pep rally. C) There were 800 freshmen at the pep rally. D) There were 805 freshmen at the pep rally.
(PRECAL)
Mathematics
2 answers:
VMariaS [17]2 years ago
8 0

Let S = the sophomores
Let R = the freshmen
Short Answer C
s + r = 1595   (1)
s + 15 = r      (2)

Substitute for r from equation (2) into equation (1)
s + s + 15 = 1595  Combine like terms
2s + 15 = 1595      Subtract 15 from both sides
2s = 1595 - 15    
2s = 1580              Divide by 2
s = 1580/2
s = 795 sophmores.

s + r = 1595
795 + r = 1595     Subtract 795 from both sides
r = 1594 - 795
r = 800 Freshmen

Answer C <<<<<<
TEA [102]2 years ago
6 0

The answer is actually 805 freshmen. The other person had a really good equation setup but they had an error after they divided 1580 by 2, it would of been 790. and if you subtract the 790 from 1580 you will get 805 freshmen.

hope this helped

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Solution to the problem

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

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