Answer:
$6500
Step-by-step explanation:
Let the amount of money invested by Lian be $x
Interest rate = 5.2% per year
interest earned in first year will be 5.2% of amount of money invested by Lian .
(note: since in first year there will be no interest accrued on interest so interest for first year is simple interest )
interest earned in one year if money invested by Lian is $x
= 5.2% of $x (1)
But , it is given in one year she received interest of 338 dollars
so, 338 dollars must be equal to 5.2% of $x
equating $338 with 5.2% of $x , we have
5.2% of x = 338
=> (5.2/100) * x = 338
=>5.2 x = 338*100
=> x = 33800/5.2 = 6500.
Thus, amount of money Lian invested is $6500.
Consider the function f ( x ) = 2479 ⋅ 0.9948x First compare this with f ( x ) po ( 1 + r ) ^ 2 We get po = 2479 And 1 + r = 0.9948 = 1 – 0.0052 r = -0.0052 < 0 Therefore, f is an exponential decay function with a decay rate of 0.0052 x 100 = 0.52%
Answer:
3
Step-by-step explanation:
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