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r-ruslan [8.4K]
2 years ago
10

The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de

viation of 29 pounds. on a raft that takes people across the river, a sign states, "maximum capacity 3,460 pounds or 20 persons." what is the probability that a random sample of 20 persons will exceed the weight limit of 3,460 pounds? use table 1. (round "z" value to 2 decimal places, and final answer to 4 decimal places.)
Mathematics
1 answer:
ad-work [718]2 years ago
4 0
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
z=\frac{173-154}{29}=0.655
Referring to a standard normal distribution table, and using z = 0.66, we find:
P(\bar x\ \textless \ 173)=0.7454
Therefore
P(\bar x\ \textgreater \ 173)=1-0.7454=0.2546
The answer is: 0.2546

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A highway had a landslide, where 3,000 cubic yards of material fell on the road, requiring 200 dump truck loads to clear. On ano
Orlov [11]
3,000 yd3 = 200 dtl
Chapter 1: Problem Solving 17 / 21

Rates Question
12 A highway had a landslide, where 3,000 cubic yards of material fell on the road, requiring 200 dump truck loads to clear. On another highway, a slide left 40,000 cubic yards on the road. How many dump truck loads would be needed to clear this slide?
3,000 yd3 = 200 dtl
40,000 yd3 × 200 dtl = 2,667 dtl
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6 0
2 years ago
Susan is attending a talk at her son's school. There are 8 rows of 10chairs where 54 parents are sitting. Susan notices that eve
kozerog [31]

Answer:

The largest possible number of adjacent empty chairs in a single row is 3

Step-by-step explanation:

The parameters given are;

The number of chairs = 8 × 10 = 80 chairs

The number of parents = 54

Sitting arrangements of parents = Alone or to one other person

Therefore;

The maximum number of parents on a row = 1 + 1 + 0 + 1 + 1 + 0 + 1 + 1 + 0 + 1 = 7

Hence when the rows have the maximum number of parents occupying the seats we have for the 8 rows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 56

But there are only 54 parents, therefore, up to the 7th row will have 7 parents while the 8th row will have only 5 parents to make the possible sitting arrangement to be as follows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 5 = 54

The sitting arrangement for the 8th row is therefore

1 + 1 + 0 + 1 + 1 + 0 + 1 + 0 + 0 + 0

Hence there will be three empty seats in the 8th row making the largest possible number of adjacent empty chairs in a single row = 3.

4 0
2 years ago
An angle bisector always creates two acute angles. find a counterexample to show that the conjecture is false.
sweet-ann [11.9K]
An acute angle is an angle that is less than 90°. An angle bisector is a ray drawn along an angle that bisects it into two equal and adjacent parts. Now, if the total angle is, say 270°, which is more than a half circle, it would result to two 135-degree angles. In this case, the angle is no longer acute, but obtuse.
5 0
1 year ago
An animal park has lions, tigers and zebras. 20% of the animals are lions and half of the animals are zebras. If there are 120 a
RoseWind [281]

Answer:

36\ tigers

Step-by-step explanation:

Let

x ----> the number of lions

y ----> the number f tigers

z ----> the number of zebras

we know that

x+y+z=120 ----> equation A

Remember that

20\%=20/100=0.20

50\%=50/100=0.50

To find out the number of lions, multiply the total animals by the percentage of lions

x=0.20(120)=24\ lions

To find out the number of zebras, multiply the total animals by the percentage of zebras

z=0.50(120)=60\ zebras

Substitute the value of x and the value of z in equation A and solve for y

24+y+60=120

y+84=120

y=36\ tigers

6 0
1 year ago
Please, I'm confuse!
Ivahew [28]

OK.  You asked for it.  Here we go.
First, let's gather up the tools we might use ...
some things that we know about triangles:

-- Every triangle:  Area = (1/2) x (length of the base) x (the height)

-- Isosceles triangle:  It has two sides that are the same length.

-- Right triangle:  It has one right angle in it. 
The sides that meet at the right angle are called the "legs". 
They form a corner there, like this      _|     .
-------------------------------------------
Now we can start using these tools to hack away at the problem.
Farmer Ted has an isosceles right triangle garden.
The problem asks us to figure out how long the legs are.

Before he changes anything, it looks like this   _|   and both of
those sides are the same length.  Call it  'x' until we figure out
what it really is.

Notice that one of them is the base of the triangle, and the other one
is the height.  So the area of this triangle is

                           (1/2) (x) (x)  or  (1/2) x² .

-------------------------------

Farmer Ted is never satisfied.  Suddenly, one day without warning, he
comes along and makes the garden bigger.  He makes one of the legs 
7  ft longer, and he makes the other one  5 ft longer.

Now the length of one leg is  (x + 7)  and the other one is (x + 5) .
They're still the base and height of the triangle, so the area of the
bigger garden is
                           (1/2) (x + 7) (x + 5).

The problem says that this area is 55 square feet more than the original
area, so look out, here comes the <em>equation </em>:

                       new area         =      old area +  bigger

                (1/2) (x + 7) (x + 5)  =      (1/2) x²  +  55

Locked in the mysterious shadowy crevices of this equation is
everything we need in order to figure out the original length of the legs ...
what we called  'x'.

At this point, we can forget about Farmer Ted, forget about the garden,
and just go back to our laboratory with this equation and solve it to find  'x'.

Let's take it slow and easy, one little step at a time:

                                     <u>(1/2) (x + 7) (x + 5)  =  (1/2) x² + 55</u>

Multiply each side by 2 :         (x + 7) (x + 5)  =         x² +  110

Expand (FOIL) the left side:     x² + 12x + 35  =         x² + 110

Subtract  x²  from each side:          12x + 35  =                 110

Subtract  35  from each side:          12x         =                  75

Divide each side by  12 :                           <em>x  =  6.25 feet</em>

==============================================

OK.  That's a very nice number.  How do we know whether it's correct ?
Let's check it out, and see if it fits the story:

Original area = (1/2 x base x height) = (0.5 x 6.25 x 6.25) = 19.53125 sq ft

One new leg = (6.25 + 7) =   13.25 ft
Other new leg = (6.25 + 5) = 11.25 ft

New area = (1/2 x base x height) = (0.5 x 13.25 x 11.25) = 74.53125 sq ft

How much bigger is the new area ?

         74.53125 - 19.53125  =  <em>55 sq ft  </em>    yay !

When we start with legs that are  6.25-ft  and go through the whole story,
the new area is exactly what the problem says it was.  So  6.25-ft  is the
correct original length of the legs, before Farmer Ted messed with it.


7 0
2 years ago
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