Jenna was selling muffins and bagels in the lobby to support the math club. Bagels sold for $0.75 and muffins sold for

N 2004, the General Social Survey (which uses a method similar to simple random sampling) asked, "Do you consider yourself athle

zmey [24]

<u>Answer-</u>

The standard error of the confidence interval is 0.63%

<u>Solution-</u>

Given,

n = 2373 (sample size)

x = 255 (number of people who bought)

The mean of the sample M will be,

$M=\frac{x}{n} =\frac{255}{2373} =0.1075$

Then the standard error SE will be,

$SE=\sqrt{\frac{M\times (1-M)}{n}}$

$SE=\sqrt{\frac{0.1075\times (1-0.1075)}{2373}}=\sqrt{\frac{0.0959}{2373}}=0.0063=0.63\%$

Therefore, the standard error of the confidence interval is 0.63%

6 0

2 years ago

Estimated quotient of 119÷23

masha68 [24]

Answer:

5...................

8 0

1 year ago

Read 2 more answers

Multiplying StartFraction 3 Over StartRoot 17 EndRoot minus StartRoot 2 EndRoot EndFraction by which fraction will produce an eq

ziro4ka [17]

The fraction which produce an equivalent fraction with a rational denominator is $\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

Explanation:

The equation is $\frac{3}{\sqrt{17}-\sqrt{2}}$

To find the rational denominator, let us take conjugate of the denominator and multiply the conjugate with both numerator and denominator.

Rewriting the equation, we have,

$\frac{3}{\sqrt{17}-\sqrt{2}}\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

Multiplying, we get,

$\frac{3(\sqrt{17}+\sqrt{2})}{(\sqrt{17})^{2}-(\sqrt{2})^{2}}$

Simplifying the denominator, we get,

$\frac{3(\sqrt{17}+\sqrt{2})}{17-2}$

Subtracting, the values of denominator,

$\frac{3(\sqrt{17}+\sqrt{2})}{15}$

Dividing the numerator and denominator,

$\frac{\sqrt{17}+\sqrt{2}}{5}$

Hence, the denominator has become a rational denominator.

Thus, the fraction which produce an equivalent fraction with a rational denominator is $\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

6 0

2 years ago

Read 2 more answers

I talk to an average of 8 customers per hour during an 8 hour shift and need to increase the amount of customers i help by 20%,

lbvjy [14]

Answer:

The number of customer needed to achieve is 34

Step-by-step explanation:

Given as :

The number of customer per hour = 8

The time taken = 8 hours

The rate of increase = 20 %

Let The increase in number of customer after 20 % increment = x

So , The number of customer after n hours = initial number × $(1+\dfrac{\textrm rate}{100})^{n}$

or, The number of customer after 8 hours = 8 × $(1+\dfrac{\textrm 20}{100})^{8}$

or, The number of customer after 8 hours = 8 × 4.2998

∴The number of customer after 8 hours = 34.39 ≈ 34

Hence The number of customer needed to achieve is 34 answer

8 0

2 years ago

If two lines are perpendicular describe the relationship between their slopes

Aloiza [94]

Perpendicular lines have slopes that are negative reciprocals. example: line a has a slope of 2/3, line b has a slope if -3/2 if they are perpendicular.

7 0

2 years ago