All we have to do here is divide 4 by 2
4 ÷ 2 = 2
Therefore, the artist can paint 2 paintings an hour making the unit rate, 2 paintings per hour.
Hope this helps
-AaronWiseIsBae
Answer:
Correct choice is C. 2 mL.
Step-by-step explanation:
Given that Ampicillin 250 mg IM every 12 hours is ordered. After reconstitution, there's 125 mg/mL. Now we need to find about how many mL would you give.
Let number of ml needed = x.
Since ratio of mg per mL will be fixed so we get equation:
Hence correct choice is C. 2 mL.
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution
We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ + v₂c₂
40(0.32) = 10(0.2) + 30c
1. 95-87 = 8 /2 = 4
2. 91 - 82 = 9 /2 = 4.5 =5
3. 91 - 87 = 4
4. B 1 times
Answer:
Step-by-step explanation:
a) Sample statistics are used to estimate population value. Since 48% is a sample proportion, therefore, it is a sample statistic.
b) For 95% confidence level, z* = 1.96.
\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}= 0.61\pm 0.61\sqrt{\frac{0.61(1-0.61)}{1578}}=0.61\pm 0.024 \ or (0.586, 0.634).
We are 95% confident that the true proportion of US residents who think marijuana should be made legal lies between 58.6% and 63.4%.
c)
\\np=1578(0.61)=962.58
\\n(1-p)=1578(1-0.61)=615.42
Since both np and n(1-p), are at least 10, the normal model is a good approximation for these data.
d) As the lower limit of confidence interval is less than 0.5, less than 50% population is also a plausible value of true proportion. This means the statement "Majority of Americans think marijuana should be legalized" is not justified.
