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melisa1 [442]
2 years ago
13

Caleb’s puppy weighs 2,250 grams. If the puppy weighed 600 grams at his last visit to the veterinarian’s office, what is the per

cent increase in the puppy’s weight rounded to the nearest whole number?
Mathematics
1 answer:
Harlamova29_29 [7]2 years ago
7 0
Answer:
The puppy's weight increased 275%

Explanation:
To get the percent of increase, we will apply the following equation:
% of increase = \frac{increase}{original value} * 100

In the given we have:
old weight = 600 grams
new weight = 2250 grams
This means that:
increase = 2250 - 600 = 1650 grams

We also have:
old value = 600 grams

Substitute in the above equation to get the % of increase as follows:
% of increase = \frac{1650}{600} *100 = 275%

Hope this helps :)
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Step 1

Find the perimeter of rectangle ABDE

we know that

the perimeter of rectangle is equal to

P=2b+2h

In this problem

b=ED=2\ units

h=AE=6\ units

substitute

P=2*2+2*6=16\ units  

Step 2

Find the perimeter of triangle BCD

we know that

the perimeter of triangle is equal to

P=BD+DC+BC

In this problem we have

BD=AE=6\ units

DC=BC

Applying the Pythagoras theorem

DC^{2}=4^{2}+3^{2}

DC^{2}=25

DC=5\ units

substitute

P=6+5+5=16\ units

Find the ratio of the perimeter of rectangle ABDE to the perimeter of triangle BCD

we have

the perimeter of rectangle is equal to

P=16\ units  

the perimeter of the triangle is

P=16\ units  

so

the ratio is equal to

\frac{16}{16} =1

therefore

<u>the answer Part 1) is the option B</u>

1

Step 3

Find the area of polygon ABCDE

we know that

The area of polygon is equal to the sum of the area of rectangle plus the area of triangle

Area of rectangle is equal to

A=AE*BD=6*2=12\ units^{2}

Area of the triangle is equal to

A=\frac{1}{2}AEh

the height h of the triangle is equal to 4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of polygon is

12\ units^{2}+12\ units^{2}=24\ units^{2}

therefore

<u>the answer part 2) is the option C</u>

24\ units^{2}


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2 years ago
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A machine called Feynman, produces output, that is 5 times its input followed by an increase of 2. Another machine called Maxwel
olganol [36]

I honestly think that the answer is a

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1 year ago
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The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is .
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Answer:

(-21,-19)

\sqrt{849}

Standard form

Step-by-step explanation:

We are given the equation of circle

x^2+y^2+42x+38y-47=0

General equation of circle:

x^2+y^2+2gx+2fy+c=0

Centre: (-g,-f)

Radius: \sqrt{g^2+f^2-c}

Compare the equation to find f, g and c from the equation

g\rightarrow 21

f\rightarrow 19

c\rightarrow -47

Centre: (-21,-19)

Radius (r) =\sqrt{21^2+19^2+47}=\sqrt{849}

Standard form of circle:

(x+21)^2+(y+19)^2=849

The centre of circle at the point (-21,-19) and its radius is \sqrt{849}.

The general form of the equation of a circle that has the same radius as the above circle is standard form.

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2 years ago
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The figure below shows the graph of f ', the derivative of the function f, on the closed interval from x = -2 to x = 6. The grap
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Answer:

x = -2

Step-by-step explanation:

From x = -2 to x = 5, f' is negative.  That means f is decreasing.

From x = 5 to x = 6, f' is positive.  That means f is increasing.

The negative area (between x = -2 and x = 5) is larger than the positive area area (between x = 5 and x = 6).  That means f decreases more than it increases.

So f is an absolute maximum at x = -2.

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The measure of central angle XYZ is StartFraction 3 pi Over 4 EndFraction radians. What is the area of the shaded sector? 32Pi u
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Answer:

<em>96π units²</em>

Step-by-step explanation:

Find the diagram attached

Area of a sector is expressed as;

Area of a sector = θ/2π * πr²

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r = 16

Substitute into the formula

area of the sector = (3π/4)/2π * π(16)²

area of the sector = 3π/8π * 256π

area of the sector = 3/8 * 256π

area of the sector = 3 * 32π

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