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Alex777 [14]
2 years ago
5

Simplify: –3(y + 2)2 – 5 + 6y What is the simplified product in standard form? y2 + y +

Mathematics
3 answers:
kondor19780726 [428]2 years ago
6 0
The answer to your question is -17
gayaneshka [121]2 years ago
3 0
-3(y+2)2-5+6y
Steps
Multiply the numbers: 3 x 2 = 6
= -6(y + 2) - 5 + 6y
Then, expand - 6(y + 2): -6y - 12
= -6y - 12-5 + 6y
Simplify
-6y - 12 - 5 + 6y
= -17
Guest1 year ago
0 1

Look it up yourself :)

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Your sister helped you get a dream job at a designer clothing store and one of the perks of the job is that you get 15% off all
Arturiano [62]

Answer:

$197.30 revenue.

Step-by-step explanation:

As long as we realise that 15% = $237.50 total revenue - 15% of that revenue $40.20 and the other 15% was totaled prior and kept to one side as seen as expenditure.

revenue = r  clothing purchase = p

r = (25 x 10 -12.50) - (p15% of e235)

r = (250 - 12.50) -( e235- p23.5 +11.73)

r = (237.50) - (expenditure 235- p35.73)

r = 237.50 -(expenditure 199.27)

r= 237.50

e = 199.27

p = 35.73

Answer with out including expenditure your sister revenue was $237.50

The 15% deduction cannot be confused with the deduction from clothes.

If we were to calculate 15% of $237.50 this would be 23.7+ 16.85 =$40.2

A different  Salary related 15% contribution payments = $40.20

If these were taken from $237.50

Then $237.50- $40.20 = $197.30 revenue, but we do not have to show expenditure in the total only the workings, which is still owed being $199.27- $40.20 already paid towards.

Extension = This means because $40.20 was deducted then expenditure still to be deducted outside of the question would be   e. $199.27 - $40.20 = 159.07 still owed. Saying that the 15% was to pay your sisters contribution to the clothes and not to the state.

5 0
2 years ago
Find a line that lies entirely in the set defined by the equation x2 + y2 − z2 = 1.
RUDIKE [14]

Answer:

x=1\,,\,y=t\,,\,z=t

Step-by-step explanation:

A line is a one-dimensional figure that has no thickness and extends infinitely in both directions.

A line segment is a line that has two end-points and a ray is a line that has one end-point.

Given equation is x^2+y^2-z^2=1

To find : a line that lies entirely in the set defined by the given equation.

Solution:

Take x=1\,,\,y=t\,,\,z=t

Check:

L.H.S=1^2+t^2-t^2=1+0=1=R.H.S

Therefore, x=1\,,\,y=t\,,\,z=t satisfy the given equation.

8 0
2 years ago
A movie theater is offering a special summer pass. Passholders pay $8 per movie for the first 5 movies and watch additional movi
Brrunno [24]
Number of movies —— C

1 —— c= 8
3——- c= 24
5—— c= 40
6 —— c = 40
15—— c = 40
3 0
2 years ago
Kristen is 64 inches tall, and she stands 12 feet away from a streetlight. If she casts an 82-inch-long shadow, how tall is the
o-na [289]

Answer:

176.39 inches or

14.70 feet

Step-by-step explanation:

Consider the right triangle made by Kristen, ground and shadow.

This triangle has one leg as 64 inches.

Next consider the right triangle formed by street light, ground upto shadow tip.

The two triangles have common angle of elevation and also another angle as 90 degrees.

Hence the two triangles would be similar

Also if A is the angle made by hypotenuse of both triangles with the ground we have

tanx=\frac{64}{82}

This value also equals by bigger triangle as

tanx=\frac{h}{82+12(12)}=\frac{h}{226}

From these two we get

h = height of street light =\frac{226(64)}{82} =176.39

6 0
2 years ago
-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz
vitfil [10]
To graph it, just graph y=-3^{-x}-6 and y=-3^x+10 and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
3^{-x}+6=3^x-10
multiply both sides by 3^x
3^0+6(3^x)=3^{2x}-10(3^x)
1+6(3^x)=3^{2x}-10(3^x)
minus 1 from both sides and minus 6(3^x) from both sides
0=3^{2x}-16(3^x)-1
use u subsitution
u=3^x
we can rewrite it as
0=u^2-16u-1
now factor
I mean use quadratic formula
for ax^2+bx+c=0 x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so for 0=u^2-16u-1, a=1, b=-16, c=-1
u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}
u=8+/-\sqrt{65}
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
u=8+\sqrt{65}=3^x
8+\sqrt{65}=3^x
if you take the log base 3 of both sides you get
log_3(8+\sqrt{65})=x
if you use ln then
ln(8+\sqrt{65})=xln(3)
then
\frac{ln(8+\sqrt{65})}{ln(3)}=x

8 0
2 years ago
Read 2 more answers
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