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Shalnov [3]
2 years ago
6

−7x−50≤−1 AND−6x+70>−2

Mathematics
1 answer:
fgiga [73]2 years ago
7 0

Answer:

-7\geq x and [-7,12) in interval notation.

Step-by-step explanation:

We have been given a compound inequality -7x-50\leq -1\text{ and }-6x+70>-2. We are supposed to find the solution of our given inequality.

First of all, we will solve both inequalities separately, then we will combine both solution merging overlapping intervals.

-7x-50\leq -1

-7x-50+50\leq -1+50

-7x\leq 49

Dividing by negative number, flip the inequality sign:

\frac{-7x}{-7}\geq \frac{49}{-7}

x\geq -7

-6x+70>-2

-6x+70-70>-2-70

-6x>-72

Dividing by negative number, flip the inequality sign:

\frac{-6x}{-6}

x

Upon merging both intervals, we will get:

-7\geq x

Therefore, the solution for our given inequality would be -7\geq x and [-7,12) in interval notation.

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Here 0.01 because it is 1 month tax.

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2 years ago
1. Three friends pooled their money to purchase a new game system that costs $298. One person
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Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → f+s+t=298

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Equation 3 → t=f-14

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93

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Andrea bought tacos from a food truck and left a 25 % 25%25, percent tip of $ 2.00 $2.00dollar sign, 2, point, 00. What was the
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Answer:

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25% ----------------> 2 $

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1 year ago
Jim's work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFractio
Blizzard [7]

Answer:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3}) and not 2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})

Step-by-step explanation:

Jim's work evaluating 2(\frac{3}{5}) ^{3} is shown:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})=2(\frac{3X3X3}{5})=2(\frac{27}{5})=\frac{54}{5}

If you look at the Second step, the exponent is taken over only the numerator. It should have been taken over both the numerator and denominator as shown below.

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})

The correct workings therefore is:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})=2(\frac{3X3X3}{5X5X5})=2(\frac{27}{125})=\frac{54}{125}

7 0
2 years ago
Read 2 more answers
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