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11111nata11111 [884]

2 years ago

9

PLEASE HELP!!!

1 answer:

Wewaii [24]2 years ago

8 0

9514 1404 393

Answer:

2∠15°
2cos(15°) +i·2sin(15°) ≈ 1.93185 +0.517638i

Step-by-step explanation:

Using Euler's formula, the 6th root is easily found.

(64i)^(1/6) = ((2^6)e^(iπ/2))^(1/6) = 2e^(iπ/12) = 2∠15°

= 2(cos(15°) +i·sin(15°)) = 2·cos(15°) +i·2·sin(15°) ≈ 1.93185 +0.517638i

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alexdok [17]

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$16:27$

Step-by-step explanation:

GIVEN: At $11:00\text{ A.M.}$ , there are $400$ members and $150$ non-members visiting a museum. After $11:00\text{ A.M.}$ , $10$ members leave every five minutes and $5$ non-members arrive every five minutes.

TO FIND: ratio of members to non-members at $1:00\text{ P.M.}$

SOLUTION:

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as after every $5$ minutes $10$ members leave

total number of $5$ minutes interval in $2$ hour $=\frac{60}{5}=12$

total members at $1:00\text{ P.M.}$ $=400-10\times24$

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Total number of non-members in museum at $11:00\text{ A.M.}$ $=150$

as after every $5$ minutes $5$ non-members arrive

total number of $5$ minutes interval in $2$ hour $=\frac{60}{5}=12$

total non-members at $1:00\text{ P.M.}$ $=150+5\times24$

$=270$

ratio of members to non-members at $1:00\text{ P.M.}$ $=\frac{\text{number of members}}{\text{number of non-members}}$

$=\frac{160}{270}$

$=\frac{16}{27}$

Hence the ratio of members to non-members at $1:00\text{ P.M.}$ is $\frac{16}{27}$

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