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morpeh [17]
2 years ago
12

A torch and a battery cost £2.50 altogether. The torch costs £2.00 more than the battery.

Mathematics
1 answer:
Genrish500 [490]2 years ago
8 0

Answer:

\frac{1}{10}

Step-by-step explanation:

Let t represent the cost of the torch and b represent the cost of the battery.

The torch and a battery cost £2.50 altogether.

\Rightarrow t+b=2.50

The torch costs £2.00 more than the battery.

\Rightarrow t=b+2.00

We substitute the second equation into the first equation to get;

\Rightarrow b+2.00+b=2.50

\Rightarrow 2b=2.50-2.00

£2.50

\Rightarrow 2b=0.50

\Rightarrow b=0.25

The price of the battery is £0.25

We express this as a fraction of the total cost which is £2.50 to get;

\frac{0.25}{2.5}=\frac{1}{10}

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Answer:

If a mixture contains 1000 pounds of Arabica beans, there should be <u>250 pounds of Robusta beans</u> in the mixture.

Step-by-step explanation:

700A+1,200R=1,000,000

700(1000) +1,200R=1,000,000 - First, plug in the A value and simplify .

700000+1,200R=1,000,000 - Then, subtract 700,000 from both sides.

1,200R=300,000 - Finally, divide by 1,200 on both sides of the equation.

R=250  - This is your value for R, or the Robusta beans.

<u>250 pounds of Robusta beans</u>

Hope this helps!

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9x^2 - 42x + 49= 64 can this be the area of a squere?
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7, 16, 25, 34, 43, ..... nth term is
vladimir2022 [97]

Answer:

79 is the ninth term.

Step-by-step explanation:

You add nine to each one.

7, 16, 25, 34, 43, 52, 61, 70, 79

79 is the ninth term.

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The system of equations
cupoosta [38]

Answer:

z = -12

Step-by-step explanation:

The given system of equations is:

xy/(x + y) = 1 ...........................(1)

xz/(x + z) = 2...........................(2)

yz/(y + z) = 3...........................(3)

From (1): x + y = xy

=> y = xy - x

y = x(y - 1)

x = y/(y - 1).......................................(4)

From (2): 2(x + z) = xz

=> 2x + 2z = xz

2x = xz - 2z

2x = z(x - 2)

z = 2x/(x - 2) ....................................(5)

From (3): 3(y + z) = yz

=> 3y + 3z = yz

3y = yz - 3z

3y = z(y - 3)

z = 3y/(y - 3)....................................(6)

Comparing (5) and (6)

2x/(x - 2) = 3y/(y - 3)

2x(y - 3) = 3y(x - 2)

2xy - 6x = 3xy - 6y

6(y - x) = xy .................................(7)

But from (1): xy = x + y

Using this in (7), we have

6(y - x) = x + y

6y - y - 6x - x = 0

5y - 7x = 0

5y = 7x

x = 5y/7................................................(8)

Using this in (4)

5y/7 = y/(y - 1)

1/(y - 1) = 5/7

(y - 1) = 7/5

y = 1 + 7/5

y = 12/5..........................................(9)

Using this in (8)

x = 5(12/5)/7 = 12/7 .......................(10)

Using (10) in (5)

z = 2x/(x - 2)

z = 2(12/7) ÷ (12/7 - 2)

= 24/7 ÷ -2/7

= 24/7 × (-7/2)

= -24/2 = -12

z = -12.

4 0
2 years ago
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