Answer: 17.3% of 45.94 km is 7.95 km
Answer:
Option b
Step-by-step explanation:
Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.
Expected observed Diff
x p(x) p(x)*1000
0 0.002 2
1 0.011 11 14 -3
2 0.115 115 15 100
3 0.123 123 130 -7
4 0.144 144
5 0.189 189
6 0.238 238
7 0.178 178
1 1000
We find that there is a large difference in 2 job application
Hence option b is right.
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
To find Kevin's age, subtract 17 by 3 to find how old Kevin is, which is 7. Then, to find Uncle rob's age, add 17 plus 3 to get 20, then multiply that by 3 to see how old Uncle Rob will be, which is 60.Then, subtract 6 from 60 to get 54.The final answer is that Kevin is 7 years old, and Uncle Rob is 54 years old. Hope this helps!