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denis23 [38]
2 years ago
11

Professor Perez used a spreadsheet to compile the data shown. Which value best approximates the

Mathematics
2 answers:
Inessa [10]2 years ago
6 0

Answer:

0.9

Step-by-step explanation:

marishachu [46]2 years ago
3 0

Answer:

The answer is "The value to this question is positive".

Step-by-step explanation:

In this question, the value of the correlation coefficient is lies between -1 to 1.

The value of n is given that is 7, and in this question one value is extra given, that is "64".

To calculate x^2 = x*x , \ \ \  y^2= y*y\\.

please find the attachment.

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Which of the following are true statements about any regular polygon? Check all that apply. A. It is a quadrilateral. B. All of
sesenic [268]
A regular polygon is a closed figure 
All its angles are equal in measure.
and all its sides are congruent
3 0
2 years ago
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Jackson is conducting an experiment for his Physics class. He attaches a weight to the bottom of a metal spring. He then pulls t
olga55 [171]
We have that the spring is going to have a sin or a cos equation. We have that the maximum distance of the spring is 6 inches and it is achieved at t=0. Let's fix this as the positive edge. Until now, we have that the function is of the form:
6sin(at+B). We have that the period is 4 minutes and hence that the time component in the equation needs to make a period (2pi) in 4 minutes. Thus 4min*a=2p, a=2p/4=pi/2. In general, a=2pi/T where a is this coefficient, T is the period. Finally, for B, since sin(pi/2)=1, we have that B=pi/2 because when t=0, we have that 6sin(B)=6. Substituting, we have f(t)=6sin(pi*t/2+pi/2)=6cos(pi*t/2)
by trigonometric identities.
7 0
1 year ago
Read 2 more answers
The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit
jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

f(x) = \lambda e^{-\lambda x} ; x > 0

Here, \lambda = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean =  \frac{1}{\lambda}  

So,  22=\frac{1}{\lambda}  ⇒ \lambda=\frac{1}{22}

SO, X ~ Exp(\lambda=\frac{1}{22})  

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

    P(X\leq x) = 1 - e^{-\lambda x}  ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

        P(X < 30)  =  1 - e^{-\frac{1}{22} \times 30}

                         =  1 - 0.2557

                         =  0.7443

7 0
2 years ago
Match with the sum of the monomial and binomial
Margarita [4]

Answer:

The answer to your question is below

Step-by-step explanation:

Just cancel the parentheses and simplify

                   Result                            Addition

                5xy² + 2x²y     ⇒                (5xy² - x²y) + 3x²y = 5xy² + 2x²y        

               -3x²y - 2xy²      ⇒                 x²y + (-2xy² - 4x²y) = -3x²y - 2xy²

                3x²y - 2xy²      ⇒               2x²y + (x²y - 2xy²) = 3x²y - 2xy²

                5x²y + xy²        ⇒                4x²y + (x²y + xy²) = 5x²y + xy²

5 0
1 year ago
The distance from Mason's house to Kevin's house is about 5 × 105 inches. The distance from Mason's house to Chloe's house is ab
olga nikolaevna [1]

Answer:

Distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.

Step-by-step explanation:

Let the distance from Mason's house to Chloe's house is x times as great as the distance from Mason's to Kevin's house.

Distance from Mason's house to Kevin's house= 5 \times 10^5 inches.

Distance from Mason's house to Chloe's house =8 \times 10^7 inches

ATQ

8 \times 10^7= x \times 5 \times 10^5 \\\frac{8 \times 10^7}{5 \times 10^5}=x\\160=x

So, distance from Mason's house to Chloe's house is 160 times as great as the distance from Mason's to Kevin's house.

Hence distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.

6 0
1 year ago
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