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2 years ago

Tim wants to build a rectangular fence around his yard. He has 42

Mathematics

2 answers:

PSYCHO15rus [73]2 years ago

5 0

Answer:

I think its D

Step-by-step explanation:

Agata [3.3K]2 years ago

3 0

Answer:

D) 6w = 42; l=14

Step-by-step explanation:

since we know,

perimeter of a rectangle = 2 ( length + width)

therefore,

=> 2 ( l + w ) = 42

but we know, l = 2w

=> 2 ( 3w ) = 42

=> 6w = 42,

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The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin

Free_Kalibri [48]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.03

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03$

$=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12$

Thus, 8.17 g separates the top 3% of the weights.

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90$

Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

7 0

2 years ago

The ratio of teachers needs to be 1:30. If there were 120 students, how many teachers would be needed?

mezya [45]

Answer:

4:120

Step-by-step explanation:

for 120 student they would be 4 teacher needed per 30 student

4:120

4 0

1 year ago

SOVA2 [1]

Answer:

Tn=13n-18

Step-by-step explanation:

Tn=-5(n-1)13

Simplify

this is using the a+(n-1)d

8 0

1 year ago

Read 2 more answers

Consider the vibrating system described by the initial value problem. (A computer algebra system is recommended.) u'' + u = 8 co

krek1111 [17]

Answer:

u(t) = -(3 + w^2 ) cos t /(1- w^2)cos t + 7 sin t + 8 cos wt /(1- w^2)

Step-by-step explanation:

The characteristic equation is k²+1 = 0,⇒k²=−1,⇒ k=±i.

the roots are k = i or -i

the solution has the form u(x)=C₁cosx+C₂sinx.

Using undetermined coefficient method

Uc(t) = Pcos wt + Qsin wt

Uc’(t) = -Pwsin wt + Qwcos wt

Uc’’(t) = -Pw^2cos wt - Qw^2sin wt

U’’ + u = 8cos wt

-Pw^2cos wt - Qw^2sin wt + Pcos wt + Qsin wt = 8cos wt

(-Pw^2 + P) cos wt + (- Qw^2 + Q ) sin wt = 8cos wt

-Pw^2 + P = 8 which implies P= 8 /(1- w^2)

- Qw^2 + Q = 8 which implies Q = 0

Uc(t) = Pcos wt + Qsin wt = 8 cos wt /(1- w^2)

U(t) = uh(t ) + Uc(t)

= C1cos t + c2 sin t + 8 cos wt /(1- w^2)

Initial value problem

U(0) = C1cos(0) + c2 sin (0) + 8 cos (0) /(1- w^2)

C1 + 8 /(1- w^2) = 5

C1 = 5 -8 /(1- w^2) = -(3 + w^2 ) /(1- w^2)

U’(t) = -C1 sin t + c2 cos t - 8 w sin wt /(1- w^2)

U’(0) = -C1 sin (0) + c2 cos (0) - 8 w sin (0) /(1- w^2) = 7

c2 = 7

u(t) = -(3 + w^2 ) cos t /(1- w^2)cos t + 7 sin t + 8 cos wt /(1- w^2)

4 0

2 years ago

Read 2 more answers

A solid oblique pyramid has a square base with an edge length of 2 cm. Angle BAC measures 45°.What is the volume of the pyramid?

Aloiza [94]

I think it's 4.8 .... I'm not 100% sure though

3 0

2 years ago

Read 2 more answers