Mya is doing a 45-minute cardio workout. She has completed 4 5 of the workout. In how many minutes will her workout be done?

Jose is blocking off several rooms in a hotel for guests coming to his wedding. The hotel can reserve small rooms that can hold

emmasim [6.3K]

Answer:

No. of large rooms = 7

No. of small rooms = 14

Set of equations

4x + 3y = 70

y = 2x

Variable definitions

No. of large rooms is x

No. of small rooms is y

Step-by-step explanation:

capacity of large rooms = 4 people

let the no. of large rooms be x

thus, total no of people which can be accommodated in x rooms = 4*x = 4x

capacity of small rooms = 3 people

let the no. of small rooms be y

thus, total no of people which can be accommodated in y rooms = 3*y = 3y

total no. of people which can be accommodated in x large room and y small room will be = 4x + 3y

It is given that total small room and large room can accommodate 70 guests

thus,

4x + 3y = 70 _________equation 1

_________________

It is also given that Jose reserved twice as many small rooms as large rooms,

so, if no. of large rooms is x and no. of small rooms is y

then

y = 2x _________equation 2

substituting value of y in equation 1 we have

4x + 3(2x) = 70

=>4x + 6x = 70

=> 10x = 70

=> x = 70/10 = 7

No. of large rooms = 7

No. of small rooms = y= 2x = 2*7 = 14

Set of equations

4x + 3y = 70

y = 2x

Variable definitions

No. of large rooms is x

No. of small rooms is y

8 0

2 years ago

4/9 divided by what equals 12

Dahasolnce [82]

(4/9)/x= 12

Multiply both sides by x
4/9=12x

Divide both sides by 12
(4/9)*(1/12)= 4/108
4/108= 1/27

Final answer: 1/27

5 0

1 year ago

Two hot air balloons are flying above a park. One balloon started at a height of 3,000 feet above the ground and is decreasing i

Stels [109]

Answer:

a

Step-by-step explanation:

its a

8 0

1 year ago

An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.

MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years, there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is $\frac{21}{3000000}==0.000007$ .

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by $q$ .

$q=7\times 10^{-6}=0.000007$ .

So, the probability of survive, $p=1-q$

$\Rightarrow p=1-7\times 10^{-6}=0.999993.$

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

$=\binom(n,r)p^rq^{n-r}$

$=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}$

$=(0.999993)^{48}=0.999664$ (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total $n$ skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

$0.9=\binom {n }{r} p^rq^{n-r}$

Here, r=n.

$\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}$

$\Rightarrow 0.9=p^n$

$\Rightarrow 0.9=(0.999993)^n$

$\Rightarrow \ln(0.9)=n\ln(0.999993)$ [ taking $\log_e$ both sides]

$\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}$

$\Rightarrow n=15051.45$

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0

2 years ago

Item 8 Question 1 A roller coaster ride holds a total of 48 passengers. The ratio of males to females on the ride is 5 : 7. Let

anastassius [24]

Here are the equations
x+y=48
x/y=5/8

but here's how I would solve it

5+7=12
48=12units
divide by 12 both sides
4=1unit

males=5 unit
4=1unit
times 5
20=5unit=males

females=7unit
4=1unit
times 7
28=7unit=females

7 0

1 year ago

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