Answer:
Step-by-step explanation:
1. .....................................................................................................
A. This is a functional relationship as the number of workers depend on the number of job sites.
B. This is a functional relationship as the amount of money is dependent on the number of withdrawals
C. This is a functional relationship as the number of vitamins depend on the number of monkeys
D. This is NOT a functional relationship as the output is a fixed value. The performance and scoring may repeat.
2. .....................................................................................................
<h3>Given</h3>
<h3>To find </h3>
<h3>Solution</h3>
- A/B =
- (62x - 100)/(2x - 3) =
- (31*2x - 31*3 - 7)/(2x - 3) =
- (31(2x - 3) -7)/(2x - 3) =
- 31 - 7/(2x - 3)
Correct option is C.
The way she put it implies that she will sell many water bottles and only one iced tea. the correct equation would be 1.25x+1.49y=100, as she may sell different amounts of each.
Answer:
The number of different possible vote totals is 184.
Step-by-step explanation:
It is provided that there are <em>N</em> = 50 people in a club.
The position of President is open. And there are <em>x</em> = 4 members running for he post of President.
So, there are <em>n</em> = <em>N</em> - <em>x</em> = 50 - 4 = 46 people voting for these 4 members.
Each member of the club has <em>x</em> = 4 possible choices.
So, the number of different possible vote totals are:
Number of different possible votes = <em>n</em> × <em>x</em>
= 46 × 4
= 184
Thus, the number of different possible vote totals is 184.
Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
Answer:
5.75x10^11
Step-by-step explanation:
quotient of 2,300 and (0.4x10^-8) is
2,300 ÷ (0.4x10^-8)
2300 = 2.3x10^3
We now have
2.3x10^3 / 0.4x10^-8
= (2.3/0.4) x ( 10^(3 - (-8))
= 5.75 x (10^(3+8))
= 5.75 x (10^11)
= 5.75x10^11
Please mark brainliest if helpful. Thanks