Answer:
The absolute brightness of the Cepheid star after a period of 45 days is -5.95
Step-by-step explanation:
Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by
M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.
From our question, it is given that P = 45 days.
So, M = –2.78(log P) – 1.35
M = –2.78(log 45) – 1.35
M = –2.78(1.6532) – 1.35
M = -4.60 - 1.35
M = -5.95
So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95
This is substitution, it's very simple once you get the hang of it!
okay, what you want to do is plug in the numbers you already have, to get the number you don't have(r).
First, you plug in the numbers.
1. P= $2000
A=$2543
t= 4(years)
r=?
2543=2000^r(4)
Secondly, you want to solve the equation.
D 7
A million apologies if I’m wrong half of my brain is still on vacation!
Answer:
Step-by-step explanation:
5/6
