<span>(serial number, model number)
That's a function mapping each serial number to its model number.
(part number, serial number)
That's not a function; the same part number is in computers with different serial numbers
</span><span> (model number, part number)
</span><span>
That one's a bit confusing. Normally a given model would have more than one part number inside so this isn't a function. But here the description says there's only one part number for each model, so that would be a function.
(model number, serial number)
Not a function, more than one serial number for a given model number.
</span>
Answer:
Jones family paid a total of $139
Step-by-step explanation:
Smith's Mountain Lake Boat provides Rental services that can be expressed as follows;
Total cost=cost per hour×number of hours rented+one time cleaning deal
For Benael's family;
Benael family total cost=Cost per hour×number of hours rented+one-time cleaning deal
where;
Benael family total cost=$226.50
Cost per hour=$25
Number of hours rented=11 am-6:30 pm=7 hours 30 minutes=7.5 hours
One time cleaning deal=x
Replacing;
226.50=(25×7.5)+x
187.5+x=226.50
x=226.50-187.5
x=39
One time cleaning deal=$39
For Jones family;
Jones family total cost=Cost per hour×number of hours rented+one-time cleaning deal
where;
Cost per hour=$25
Number of hours rented=9 am-1 pm=4 hours
One time cleaning deal=$39
Replacing;
Jones family total cost=(25×4)+39
Jones family total cost=$139
Jones family paid a total of $139
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Answer:
Yes it is
Step-by-step explanation:
It is 104777
