14 ounces of olive oil for $3.59

Condense each expression. 5 log5 x - 1/4 log5 (8 -x)

allsm [11]

Step-by-step explanation:

5 log₅ x − ¼ log₅ (8−x)

log₅ x⁵ − log₅ (8−x)^¼

log₅ x⁵ − log₅ ∜(8−x)

log₅ (x⁵ / ∜(8−x))

4 0

2 years ago

"a guest orders a drink that contains 1½ ounces of 80-proof vodka and 12 ounces of beer. approximately how many drinks does this

frosja888 [35]

A guest orders a drink = 1½ ounces of 80-proof vodka and 12 ounces of beer
it means it contains 2 drinks.
Because 3 ounces of 80 proof vodka is considered as 2 drinks and half of that will be considered as 1 drink, and 12 ounces of beer is considered as one drink so the total drinks this beverage contains is two drinks.

7 0

2 years ago

Read 2 more answers

K is the midpoint of segment HL . H has coordinates (1, -7 ) , and K has coordinates(-9, 3 ). Find the coordinates of other end

Andrei [34K]

Answer:

Coordinates of other end point L = ( -19, 13 )

Explanation:

The mid point of the coordinates (a,b) and (c,d) is given by $(\frac{a+c}{2},\frac{b+d}{2})$

Here we have (a,b) = (1,-7) and $(\frac{a+c}{2},\frac{b+d}{2})$ = (-9,3) , we need to find (c,d).

$\frac{a+c}{2} =-9\\ \\ 1+c=-18\\ \\ c=-19\\\\ \frac{b+d}{2} =3\\ \\ -7+d=6\\ \\ d=13$

So coordinates of other end point L = ( -19, 13 )

8 0

2 years ago

Read 2 more answers

In the diagram, transversal t cuts across the parallel lines a and b. Match the pairs of angles with the relationship that shows

charle [14.2K]

we know that

case a) alternate exterior angles

m∠2=m∠7 --------> by alternate exterior angles

m∠1=m∠8 --------> by alternate exterior angles

case b) alternate interior angles

m∠3=m∠6 --------> by alternate interior angles

m∠5=m∠4 --------> by alternate interior angles

case c) corresponding angles

m∠1=m∠5 --------> by corresponding angles

m∠3=m∠7 --------> by corresponding angles

m∠2=m∠6 --------> by corresponding angles

m∠4=m∠8 --------> by corresponding angles

case d) vertical angles

m∠1=m∠4 --------> by vertical angles

m∠2=m∠3 --------> by vertical angles

m∠5=m∠8 --------> by vertical angles

m∠6=m∠7 --------> by vertical angles

therefore

the answer in the attached figure

5 0

2 years ago

After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ

icang [17]

Answer:

a) Upper Control Limit = 0.10

Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

computer manufacturer examined samples of calls to determine

the frequency of wrong advice given to callers. Each sample

consisted of 100 calls.

SAMPLE 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

Number of errors 5 3 5 7 4 6 8 4 5 9 3 4 5 6 6 7

To find - a. Determine 95 percent limits.

b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

= 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

= 0.0544

⇒P = 0.0544

Now,

Q = 1-P

= 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = $\sqrt{\frac{P.Q}{N} }$

= 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

= 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

= 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0

2 years ago