<h2>
Dimension of trash bin is 6 ft x 6 ft x 3ft .</h2>
Step-by-step explanation:
Let h be the height of box and a be the side of base square.
We have 108 ft² material.
Surface area of trash bin = 108 ft²
Surface area of trash bin = a² + 4 ah
a² + 4 ah = 108
4ah = 108 - a²
Volume of trash bin, V = a²h
At maximum volume differentiation of volume will be zero
Surface area of trash bin = a² + 4 ah = 108
36 + 4 x 6 x h = 108
h = 3 ft
Dimension of trash bin is 6 ft x 6 ft x 3ft .
Answer:34.4
Step-by-step explanation:
172.5-137.1=34.4
Answer:
The complement of the given set in interval notation is![(-\infty,-5]\cup(6,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-5%5D%5Ccup%286%2C%5Cinfty%29)
. It can we written as (-inf,5]U(6,inf).
Step-by-step explanation:
The given set in interval notation is
(−5,6]
It means the set is defined as
If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.
Here, universal set is R, the set set of all real numbers.
The complement of the given set is
Complement of the given set in interval notation is
![A^c=(-\infty,-5]\cup(6,\infty)](https://tex.z-dn.net/?f=A%5Ec%3D%28-%5Cinfty%2C-5%5D%5Ccup%286%2C%5Cinfty%29)
Therefore the complement of the given set in interval notation is. It can we written as (-inf,5]U(6,inf).
Answer: it’s b, f(x)=54(2/3)^x-1
Step-by-step explanation:
Answer:
Step-by-step explanation:
The side of the square = 3^2/7
Use the law of exponents . If the power is a fraction, that means it is
3^2/7 = 3^2 x 1/7 = 7√9
To find the area you multiply this by itself.
This gives you 1.87...
Hope this helps
