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dezoksy [38]
2 years ago
9

Nancy used 14 yards of fabric to make flags for one third of the drill team. How much fabric would Nancy need to make flags for

the whole team
Mathematics
2 answers:
Kipish [7]2 years ago
7 0

If all the flags use material at the same rate, Nancy will need 3 times the fabric to make 3 times the number of flags. Nancy needs 3×(14 yd) = 42 yd for the whole team.

xenn [34]2 years ago
3 0
Since 14 is a 1/3 (third) of the team, Nancy wouls need 42 yards of fabric by multiplying the 14 by 3 innorder to get the amount for the entire team.

Answer=42
i hope this helps!!
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Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The
kobusy [5.1K]

Answer:

20 and 16

Step-by-step explanation:

Let us find x and y.

x – y = 4 _____(1)

x/2 + y/2= 18___(2)

Multiply (2) by 2 and add to (1)

  x - y = 4

+<u>(x + y = 36)</u>

 <u>2x   =   40</u>

=> x = 40 / 2 = 20

From (1):

20 - y = 4

=> y = 20 - 4 = 16

The two numbers are 20 and 16.

6 0
2 years ago
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A dartboard has 10 equally sized slices numbered from 1 to 10. Some are grey and some are white. The slices numbered 1,2 ,3 ,5 ,
hram777 [196]

Answer:

P(X) is 7/10

P(not X) is 3/10

Step-by-step explanation:

The total is 10 so thats ur denominator

The probability of landing on a grey area is 7/10

The probability of not landing on a grey area is 3/10

Hope this helps

5 0
2 years ago
A botanist collected one leaf at random from each of 10 randomly selected mature maple trees of the same species. The mean and t
Zarrin [17]

Answer:

One sample t-test for population mean would be the most appropriate method.

Step-by-step explanation:

Following is the data which botanist collected and can use:

  • Sample mean
  • Sample Standard Deviation
  • Sample size (Which is 10)
  • Distribution is normal

We have to find the best approach to construct the confidence interval for one-sample population mean. Two tests are used for constructing the confidence interval for one-sample population mean. These are:

  • One-sample z test for population mean
  • One-sample t test for population mean

One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.

Considering the data botanist collected, One-sample t test would be the most appropriate method as we have all the required data for this test. Using any other test will result in flawed intervals and hence flawed conclusions.

Therefore, One-sample t-test for population mean would be the most appropriate method.

8 0
2 years ago
Kendra is buying bottled water for a class trip. She has 16 bottles left over from the last trip. She buys bottles by the case t
maria [59]
Answer=6

Given the information, the following equation can be made, where x is equal to the number of cases she needs to buy.

160=16+24x
subtract 16 from both sides
144=24x
divide both sides by 24
6=x

She will have to buy 6 cases to have a total of 160 water bottles.
8 0
2 years ago
Read 2 more answers
A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall
avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

P(A \cap B) = 0.125\frac{1}{7} = 0.0179

What is the probability that today is Monday?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286

0.0286 = 2.86% probability that today is Monday.

4 0
2 years ago
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