Question

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an hourly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford.

Answer 1

This Question is Incomplete

Complete Question

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.

Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1 answer:

A. 28 + 65H < 250

B. 28 + 65H > 250

C. 65 + 28H < 250

D. 65 +28H > 250

2) What is the largest whole number of hours that Anand can afford?​

Answer:

1) C. 65 + 28H < 250

2) 6 hours

Step-by-step explanation:

We are told in the question that:

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours.

Hences we have:

$65 + 28 × H

We are told that:

Anand would like to spend no more than $250,

Hence,our equation becomes:

$65 + 28H ≤ $250

Where H = Hourly rates of the plumber.

1) Which inequality describes this scenario?

From the given options and our calculations above, Option C) 65 + 28H < 250 is the correct answer

2) What is the largest whole number of hours that Anand can afford?​

We would use our equation above to solve for this.

65 + 28H < 250

= 65 + 28H ≤ 250

We convert or inequality sign to equal to sign

= 65 + 28H = 250

28H = 250 - 65

28H = 185

H = 185/28

H = 6.6071428571 hours

Therefore, the largest whole number of hours that Anand can afford is 6 hours

Answer 2

Answer:

65+28H $\leq$ 250

6 hours

Step-by-step explanation: The answer from Khan