First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg
For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80
For median, you find the middle number (76kg)
For mode, you find the number that appears the most (61kg)
Mean: 80
Median: 76
Mode: 61
Solution:
we are given that
Nathan takes 42 minutes to thread a distance of 4.5 miles on a threadmill.
we have been asked to find the average distance covered in one minute.
Using the concept of unity we can write
Since Nathan takes 42 minutes to cover a distance of 4.5 miles.
So in 1 minute Nathan will cover a distance of 
Hence avearge distance covered in one minute is 1.1 miles.
Answer:
Sebastian didn't interpret the numbers correctly (See explanation)
Step-by-step explanation:
If you go up an elevator, you are gaining floors, so the number is positive.
If you go down an elevator, you are losing floors, so the number is positive.
Looking at the statement, he went 7 floors up to his room, then 9 floors down to the parking garage this can be represented as
, since the 7 is positive and the 9 is negative.
Sebastian described the movement as
, which is wrong - 9 should be -9 and -7 should be 7.
Hope this helped!
Answer:
4 games
Step-by-step explanation:
<em>Robert called two bowling centers, Fannin Lanes and Fun Times Lanes, to déterminé the cost to bowl.</em>
Let x number of games played
y represents total cost to bowl
- Fannin Lanes charges 2.50 per games plus 2 for shoe rental
y = 2.50x + 2
- Fun Time Lanes charges 2 per game plus 4 for shoe rental.
y = 2x + 4
<u><em>If total cost to bowl be same at both center</em></u>
2.50x + 2 = 2x + 4
2.5x - 2x = 4-2
0.5x = 2
x = 4
Hence, 4 games will the cost to bowl be the same at both center.
Answer:
cl + 1/(N+1)
Step-by-step explanation:
If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=cl
And we know that the (N+1)th harmonic number can be found by doing
1+1/2+1/3+1/4+...+1/N+1/(N+1)
=cl + 1/(N+1)
The (N+1)th harmonic number is cl + 1/(N+1) given that the Nth term is cl
Other way to see the answers:
Maybe you want to write it as a single fraction so you have
[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)