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ra1l [238]
2 years ago
13

N ÷ 3 +n for n =6 can you guys help me

Mathematics
1 answer:
Ludmilka [50]2 years ago
8 0

Answer:

8 is your answer

Step-by-step explanation:

First plug in 6

6÷3+6

Then divide 6/3 which is 2

so 2+6 is 8

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Find the x-intercepts for the parabola defined by this equation: y=-3x^2-6x+9
JulijaS [17]
X=1,
X=-3
Use Photomath it helps
7 0
2 years ago
Three students solve a challenge math problem. Every day, the number of students who solve the problem doubles. There are 384 st
attashe74 [19]

OK, so this is assuming we are considering that the first three kids to solve ARE NOT in the first day.


So we have 3 kids and it doubles

Day 1 : 6

Day 2 : 12

Day 3 : 24

Day 4 : 48

Day 5 : 96

Day 6 : 192

Day 7: 384


So it should take 7 days or a week to solve all the problems.

The equation:

(3 * 2)^x = 384


8 0
2 years ago
Read 2 more answers
A 100-square grid has 70 shaded squares. Explain how you could express this model as a fraction, percent, and decimal.
slava [35]
The fraction of squares shaded to total squares is 70/100  or 7/10
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6 0
2 years ago
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To find the number in a square multiply the numbers in the two circles connected to it brainly
max2010maxim [7]

Answer:

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6 0
2 years ago
For a certain type of copper wire, it is knownthat, on the average, 1.5 flaws occur per millimeter.Assuming that the number of f
mario62 [17]

Answer:

The probability that no flaws occur in a certain portion of wire of length 5 millimeters =  1.1156 occur / millimeters

Step-by-step explanation:

<u>Step 1</u>:-

Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.

by  Poisson random variable given that λ = 1.5 flaws/millimeter

Poisson distribution P(X= r) = \frac{e^{-\alpha } \alpha ^{r} }{r!}

<u>Step 2:</u>-

The probability that no flaws occur in a certain portion of wire

P(X= 0) = \frac{e^{-1.5 } \(1.5) ^{0} }{0!}

On simplification we get

P(x=0) = 0.223 flaws occur / millimeters

<u>Conclusion</u>:-

The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 5 X P(X=0) = 5X 0.223 = 1.1156 occur / millimeters

5 0
2 years ago
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