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olga nikolaevna [1]
2 years ago
11

A diver begins at 140 feet below sea level. She descends at a steady rate of 7 feet per minute for 4.5 minutes. Then, she ascend

s 112.2 feet. What is her current depth?
Mathematics
2 answers:
Travka [436]2 years ago
4 0
Alright lets look at this problem the first step is to find out how far down she went in 4.5 minutes. so 7*4.5=31.5 ft next what you have to do is add 31.5 ft to 140 ft which is 171.5 ft next you need to subtract 112.2 ft from 171.5 ft which means that the divers current depth must be 59.3 Ft.
Sauron [17]2 years ago
4 0

Answer:

The diver begins at -150 feet and then descends at 5 feet/minute for 3.5 minutes, which could be represented by (-5)(3.5). The diver then ascends 122.2 feet, which is a positive number. The expression would be -150 + (-5)(3.5) + 122.2. Using order of operations, you get that the diver’s current depth is 45.3 feet below sea level.

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6th graders = 52%
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8th, 6th then 7th 
7 0
2 years ago
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During a certain week, a post office sold Rs.280 worth of 14-paisas stamps. How many of these stamps did they sell?
Novosadov [1.4K]
So basically ...

You convert the rupees in paisas. One rupee is equal to one hundred paisas, so ...

280 × 100 = 28,000

And then we divide,

28,000 ÷ 14 = 2000

The post office sold 2000 stamps!

Hope this helped! :)
6 0
2 years ago
A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif
VashaNatasha [74]

Answer:

(A)

P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx  = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192

(B)

Then the cumulative function would be

CF(x) = 1.25x - 0.25x^5       if   0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx  = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192

(B)

For any  x you are looking for the probability P(X \geq x)  which is

P(X \geq x)  = \int\limits_{-\infty}^{x}  1.25(1-t^4) dt = \int\limits_{0}^{x}  1.25(1-t^4) dt = 1.25x - 0.25x^2

Then the cumulative function would be

CF(x) = 1.25x - 0.25x^5       if   0<x<1

0 otherwise.

5 0
2 years ago
A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as
Orlov [11]
A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as a control chart.
6 0
2 years ago
A steel pipe 100 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If thee density of the steel is 7.8 g
ELEN [110]

Answer:

The mass of the pipe is 465\ g

Step-by-step explanation:

step 1

Find the volume of the steel pipe

The volume is equal to the area of outside circle minus the area of inside circle, multiplied by the length of the pipe

so

V=\pi [r2^{2}-r1^{2}]L

we have

r2=2/2=1\ cm ---> the radius is half the diameter

r1=1.8/2=0.9\ cm ---> the radius is half the diameter

L=100\ cm

\pi=3.14

substitute

V=(3.14)[1^{2}-0.9^{2}](100)=59.66\ cm^{3}

step 2

Find the mass

The mass is equal to the density multiplied by the volume

so

m=7.8(59.66)=465\ g

8 0
2 years ago
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