We use the trinomial theorem to answer this question. Suppose we have a trinomial (a + b + c)ⁿ, we can determine any term to be:
[n!/(n-m)!(m-k)!k!] a^(n-m) b^(m-k) c^k
In this problem, the variables are: x=a, y=b and z=c. We already know the exponents of the variables. So, we equate this with the form of the trinomial theorem.
n - m = 2
m - k = 5
k = 10
Since we know k, we can determine m. Once we know m, we can determine n. Then, we can finally solve for the coefficient.
m - 10 = 5
m = 15
n - 15 = 2
n = 17
Therefore, the coefficient is equal to:
Coefficient = n!/(n-m)!(m-k)!k! = 17!/(17-5)!(15-10)!10! = 408,408
Answer:
see the explanation
Step-by-step explanation:
we know that
A gross is equal to 120 ones or ten dozen
what is 15 tens - 1 gross
we know that
15 tens means ----> That you are adding 10, 15 times or multiplying 10 by 15, which gives you
1 gross means ---> That you are adding 10, 12 times or multiplying 10 by 12
which gives you
so
The algebraic expression of 15 tens - 1 gross is equal to
Convert to word expression
3 tens
Elisa, e = 11mins
Prenav,p = 13mins
time to complete, t
1 = t( 1/11 + 1/13) = t (24/143)
t = 143/24 = 5.96min
Answer is A 5.96mins
<span>no está en mi equipo lo siento</span>
Quadratic equation: ax² + bx + c =0
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6
x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31
