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Alex787 [66]
2 years ago
13

Consider purchasing a system of audio components consisting of a receiver, a pair of speakers, and a CD player. Let A1 be the ev

ent that the receiver functions properly throughout the warranty period, A2 be the event that the speakers function properly throughout the warranty period, and A3 be the event that the CD player functions properly throughout the warranty period. Suppose that these events are (mutually) independent with P(A1) 5 .95, P(A2) 5 .98, and P(A3) 5 .80.(a) What is the probability that all three components function properly throughout the warranty period?(b) What is the probability that at least one component needs service during the warranty period?
Mathematics
1 answer:
Tomtit [17]2 years ago
5 0

Answer: ggg

Step-by-step explanation:

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The winners of a carnival game draw a ticket from a box to determine their prize. Each winner draws a ticket and places it back
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Answer:

He generates a random whole number from 1 to 3.

Step-by-step explanation:

Each winner has 3 possibilities, gets cotton candy, gets a shirt, or gets a keychain. We can asign each of this possibiltiies a number, 1 for cotton candy, 2 for the shirt and 3 for a keychain. So, for a simulation, its enough to take one of this whole numbers for each winner.

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2 years ago
Each batch of Mrs. Crawley’s Toffee makes 14 pieces of toffee. If sandy needs 8 dozen pieces of toffee, how many batches does sh
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7 batches of cookies 14 x 7=98 whereas sandy needs 12 x 8=96 ,so 7 batches would be perfect
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A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is___ units. The point (
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<span>A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is 5_ units. The points(-7,5) and (-7,-1</span>) lie on this circle.
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2 years ago
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Problem 2.2.4 Your Starburst candy has 12 pieces, three pieces of each of four flavors: berry, lemon, orange, and cherry, arrang
kkurt [141]

Answer:

a) P=0

b) P=0.164

c) P=0.145

Step-by-step explanation:

We have 12 pieces, with 3 of each of the 4 flavors.

You draw the first 4 pieces.

a) The probability of getting all of the same flavor is 0, because there are only 3 pieces of each flavor. Once you get the 3 of the same flavor, there are only the other flavors remaining.

b) The probability of all 4 being from different flavor can be calculated as the multiplication of 4 probabilities.

The first probability is for the first draw, and has a value of 1, as any flavor will be ok.

The second probability corresponds to drawing the second candy and getting a different flavor. There are 2 pieces of the flavor from draw 1, and 9 from the other flavors, so this probability is 9/(9+2)=9/11≈0.82.

The third probability is getting in the third draw a different flavor from the previos two draws. We have left 10 candys and 4 are from the flavor we already picked. Then the third probabilty is 6/10=0.6.

The fourth probability is getting the last flavor. There are 9 candies left and only 3 are of the flavor that hasn't been picked yet. Then, the probability is 3/9=0.33.

Then, the probabilty of picking the 4 from different flavors is:

P=1\cdot\dfrac{9}{11}\cdot\dfrac{6}{10}\cdot\dfrac{3}{9}=\dfrac{162}{990}\approx0.164

c) We can repeat the method for the previous probabilty.

The first draw has a probability of 1 because any flavor is ok.

In the second draw, we may get the same flavor, with probability 2/11, or we can get a second flavor with probability 9/11. These two branches are ok.

For the third draw, if we have gotten 2 of the same flavor (P=2/11), we have to get a different flavor (we can not have 3 of the same flavor). This happen with probability 9/10.

If we have gotten two diffente flavors, there are left 4 candies of the picked flavors in the remaining 10 candies, so we have a probabilty of 4/10.

For the fourth draw, independently of the three draws, there are only 2 candies left that satisfy the condition, so we have a probability of 2/9.

For the first path, where we pick 2 candies of the same flavor first and 2 candies of the same flavor last, we have two versions, one for each flavor, so we multiply this probability by a factor of 2.

We have then the probabilty as:

P=2\cdot\left(1\cdot\dfrac{2}{11}\right)\cdot\left(\dfrac{9}{10}\cdot\dfrac{2}{9}\right)+\left(1\cdot\dfrac{9}{11}\cdot\dfrac{4}{10}\cdot\dfrac{2}{9}\right)\\\\\\P=2\cdot\dfrac{36}{990}+\dfrac{72}{990}=\dfrac{144}{990}\approx0.145

5 0
2 years ago
The area of an extra large circular pizza from Gambino's Pizzeria is 484\pi \text{ cm}^2484π cm 2 484, pi, space, c, m, start su
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Answer:

The diameter of an extra large pizza from Gambino's Pizzeria is 44\ cm

Step-by-step explanation:

we know that

The area of a circle (circular pizza ) is equal to

A=\pi r^{2}

we have

A=484\pi\ cm^{2}

substitute in the formula and solve for the radius r

484\pi=\pi r^{2}

Simplify

484=r^{2}

r=22\ cm

Find the diameter

Remember that the diameter is two times the radius

D=2(22)=44\ cm

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2 years ago
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